laravel 直接从模型实例化查询构建器
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Instance the query builder directly from model
提问by David Rodrigues
When I do something like SomeModel::with('user')it returns a Query\Builderinstance. How can I get this instance without need call the with()(or similar)?
当我做类似的事情时，SomeModel::with('user')它会返回一个Query\Builder实例。我怎样才能在不需要调用with()（或类似的）的情况下获得这个实例？
For instance, I tried it: new SomeModel, but it'll returns obviously the instance of my model, not the query builder (not worked to me). The SomeModel::getQuerynot works too, because it returns a Query\Buildernot related to my model.
例如，我尝试了它：new SomeModel，但它显然会返回我的模型的实例，而不是查询构建器（对我不起作用）。也SomeModel::getQuery不起作用，因为它返回一个Query\Builder与我的模型无关的。
I need it to I setup based on some conditionals. So initially it need be empty, like it:
我需要它根据一些条件进行设置。所以最初它需要是empty，像这样：
$someBuilder = SomeModel::getQueryBuilder(); // eg.
if(condition()) {
$someBuilder->where(...);
}
$someResults = $someBuilder->get();
回答by Joseph Silber
Use the static querymethod:
使用静态query方法：
$query = User::query();
Additionally, you can use the whenmethod to chain these conditionals directly onto the query builder itself:
此外，您可以使用该when方法将这些条件直接链接到查询构建器本身：
$results = SomeModel::query()->when(condition(), function ($query) {
$query->where(...);
})->get();
This is functionally equivalent to the imperative ifclause.
这在功能上等同于祈使if句。
