Java Scanner 类读取字符串
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Java Scanner class reading strings
提问by marcoamorales
I got the following code:
我得到以下代码：
int nnames;
String names[];
System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
names = new String[nnames];
for (int i = 0; i < names.length; i++){
System.out.print("Type a name: ");
names[i] = in.next();
}
System.out.println(names[0]);
When I run this code, the scanner will only pick up the first name and not the last name. And it will sometimes skip a line when trying to enter a name, it will show up as if I had left the name blank and skip to the next name. I don't know what's causing this.
当我运行此代码时，扫描仪将只选择名字而不是姓氏。它有时会在尝试输入名称时跳过一行，它会显示为好像我将名称留空并跳到下一个名称。我不知道是什么原因造成的。
I hope someone can help me!
我希望有一个人可以帮助我！
EDIT: I have tried in.nextLine(); it fixes the complete names but it still keeps a line, here is an example of the output:
编辑：我试过 in.nextLine(); 它修复了完整的名称，但仍保留一行，以下是输出示例：
How many names are you going to save: 3
Type a name: Type a name: John Doe
Type a name: John Lennon
回答by rogeriopvl
Instead of:
代替：
in.next();
Use:
利用：
in.nextLine();
nextLine()reads the characters until it finds a new line character '\n'
nextLine()读取字符直到找到新行字符 '\n'
回答by CPerkins
After your initial nextInt(), there's still an empty newline in your input. So just add a nextLine() after your nextInt(), and then go into your loop:
在您最初的 nextInt() 之后，您的输入中仍然有一个空的换行符。所以只需在 nextInt() 之后添加一个 nextLine()，然后进入循环：
...
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
in.nextLine(); // gets rid of the newline after number-of-names
names = new String[nnames];
for (int i = 0; i < names.length; i++){
System.out.print("Type a name: ");
names[i] = in.nextLine();
}
...
...
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
in.nextLine(); // gets rid of the newline after number-of-names
names = new String[nnames];
for (int i = 0; i < names.length; i++){
System.out.print("Type a name: ");
names[i] = in.nextLine();
}
...
回答by Amarghosh
Scanner.nextstops reading when it encounters a delimiter, which is a whitespace. Use the nextLinemethod instead.
Scanner.next在遇到分隔符（空格）时停止读取。请改用该nextLine方法。
回答by user3542612
Try using:
尝试使用：
System.out.println()
Instead of:
代替：
System.out.print()
