JQuery :not() 选择器结合属性包含选择器
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JQuery :not() selector combined with Attribute Contains selector
提问by rlemon
So I have a large form and I need to select all elements that have a specific identifier in their id value.
所以我有一个很大的表单，我需要选择所有在其 id 值中具有特定标识符的元素。
$("[id*=some-value]")
This works wonderfully! Now I need to filter out of these results any elements that have another key identifier in their id values
这非常有效！现在我需要从这些结果中过滤掉在其 id 值中具有另一个键标识符的任何元素
$("[id*=some-value]:not([id*=some-other-value])")
which obviously is not working for me.
这显然对我不起作用。
Currently the only element I am filtering is a checkbox so I can just use
目前我过滤的唯一元素是一个复选框，所以我可以使用
$("[id*=add-contact-form]:not(:checkbox)")
however I would still like to know how to combine the two selector methods.
但是我仍然想知道如何组合这两种选择器方法。
采纳答案by David Hancock
What you already have seems to be working fine for me?
你已经拥有的似乎对我来说很好用？
I suggest taking a look at your code and seeing if there is some underlying issue preventing that jQuery selector from working.
我建议查看您的代码，看看是否存在一些阻止 jQuery 选择器工作的潜在问题。
回答by Mrchief
First of all, if your id contains "some-value" literally, then it'll automatically exclude "some-other-value".
首先，如果您的 id 字面上包含“some-value”，那么它会自动排除“some-other-value”。
For it to be able to pick up the other elements, the idhas to match upto a point: "some-other-value" -> "some-value-other" (see how the first 2 portions match)
为了能够获取其他元素，id必须匹配到一个点：“some-other-value”->“ some-value-other”（查看前两个部分如何匹配）
You can try this:
你可以试试这个：
$("[id*=add-contact-form]").not(":checkbox");
or
或者
$("[id*=some-value]").not("[id*=some-value-other]");
回答by A.J.
This works for me. Simple, less code, and attractive.
这对我有用。简单，更少的代码，而且很有吸引力。
$('*[id=some_id] option[value!=]')
$('*[id=some_id] option[value!=]')
It will select all the options which have value attribute set to something and ignore with empty ones.
它将选择所有 value 属性设置为某物的选项，并忽略空的选项。
