Java Mockito 验证方法调用的顺序/顺序

Mockito verify order / sequence of method calls

提问by froi

Is there a way to verify if a methodOneis called before methodTwoin Mockito?

有没有办法验证methodOne之前是否methodTwo在 Mockito 中调用了 a？

public class ServiceClassA {
    public void methodOne(){}
 }

public class ServiceClassB {
    public void methodTwo(){}
 }

---

---

public class TestClass {
    public void method(){
        ServiceClassA serviceA = new ServiceClassA();
        ServiceClassB serviceB = new ServiceClassB();
        serviceA.methodOne();
        serviceB.methodTwo();
    }
}

采纳答案by Koitoer

InOrderhelps you to do that.

InOrder帮助你做到这一点。

ServiceClassA firstMock = mock(ServiceClassA.class);
ServiceClassB secondMock = mock(ServiceClassB.class);

Mockito.doNothing().when(firstMock).methodOne();   
Mockito.doNothing().when(secondMock).methodTwo();  

//create inOrder object passing any mocks that need to be verified in order
InOrder inOrder = inOrder(firstMock, secondMock);

//following will make sure that firstMock was called before secondMock
inOrder.verify(firstMock).methodOne();
inOrder.verify(secondMock).methodTwo();

回答by LaurentG

Yes, this is described in the documentation. You have to use the InOrderclass.

是的，这在文档中有所描述。您必须使用InOrder类。

Example (assuming two mocks already created):

示例（假设已经创建了两个模拟）：

InOrder inOrder = inOrder(serviceAMock, serviceBMock);

inOrder.verify(serviceAMock).methodOne();
inOrder.verify(serviceBMock).methodTwo();

回答by entpnerd

Note that you can also use the InOrderclass to verify that various methods are called in order on a single mock, not just on two or more mocks.

请注意，您还可以使用InOrder类来验证在单个模拟上是否按顺序调用了各种方法，而不仅仅是在两个或多个模拟上。

Suppose I have two classes Fooand Bar:

假设我有两个类Foo和Bar：

public class Foo {
  public void first() {}
  public void second() {}
}

public class Bar {
  public void firstThenSecond(Foo foo) {
    foo.first();
    foo.second();
  }
}

I can then add a test class to test that Bar's firstThenSecond()method actually calls first(), then second(), and not second(), then first(). See the following test code:

然后我可以添加一个测试类来测试它Bar的firstThenSecond()方法实际调用first()，然后second()，而不是second()，然后first()。请看以下测试代码：

public class BarTest {
  @Test
  public void testFirstThenSecond() {
    Bar bar = new Bar();
    Foo mockFoo = Mockito.mock(Foo.class);
    bar.firstThenSecond(mockFoo);

    InOrder orderVerifier = Mockito.inOrder(mockFoo);
    // These lines will PASS
    orderVerifier.verify(mockFoo).first();
    orderVerifier.verify(mockFoo).second();

    // These lines will FAIL
    // orderVerifier.verify(mockFoo).second();
    // orderVerifier.verify(mockFoo).first();
  }
}

回答by Thracian

With BDD it's

有了 BDD，它是

@Test
public void testOrderWithBDD() {


    // Given
    ServiceClassA firstMock = mock(ServiceClassA.class);
    ServiceClassB secondMock = mock(ServiceClassB.class);

    //create inOrder object passing any mocks that need to be verified in order
    InOrder inOrder = inOrder(firstMock, secondMock);

    willDoNothing().given(firstMock).methodOne();
    willDoNothing().given(secondMock).methodTwo();

    // When
    firstMock.methodOne();
    secondMock.methodTwo();

    // Then
    then(firstMock).should(inOrder).methodOne();
    then(secondMock).should(inOrder).methodTwo();


}