javascript 如何在 PHP 的 HTML 页面中动态更改登录和注销链接?
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How to change login and logout links dynamically in HTML page in PHP?
提问by pratim_b
I have the following HTML code. I have 2 php files: login.php and logout.php. When any user first comes to my page, I would like him to see the login link. After clicking log in (which I will process with my login.php file) I want to change that login link to logout (and on click of that logout.php file will be processed)
我有以下 HTML 代码。我有 2 个 php 文件:login.php 和 logout.php。当任何用户第一次访问我的页面时,我希望他看到登录链接。单击登录(我将用我的 login.php 文件处理)后,我想将该登录链接更改为注销(单击该 logout.php 文件将被处理)
In the following code, how could I dynamically change login and logout links? Currently I have given 2 different links for login and logout which is not a good idea.
在以下代码中,如何动态更改登录和注销链接?目前我提供了 2 个不同的登录和注销链接,这不是一个好主意。
<header class="group">
<nav class="group">
<ul>
<li><a href="register.php" title="">Register</a></li>
<li><a href="login.php" title="">Login</a></li>
<li><a href="logout.php" title="">Logout</a></li>
</ul>
</nav>
</header>
回答by Nauphal
Try this.
试试这个。
You need to set a variable $logged_user
to identify whether the user is logged in or not
需要设置一个变量$logged_user
来标识用户是否登录
<header class="group">
<nav class="group">
<ul>
<?php if ($logged_user) { ?>
<li><a href="logout.php" title="">Logout</a></li>
<?php } else { ?>
<li><a href="register.php" title="">Register</a></li>
<li><a href="login.php" title="">Login</a></li>
<?php } ?>
</ul>
</nav>
回答by pratim_b
I am assuming you are using a session to check whether user logged in or not. If not, create a session variable and set once logged in. Clear the session variable on log out. So you can check
我假设您正在使用会话来检查用户是否登录。如果没有,请创建一个会话变量并在登录后设置。注销时清除会话变量。所以你可以检查
if(isset($_SESSION['logged_in'])){
//your logout link
}else{
//your login link
}
回答by Karuppiah RK
<?php
if ($signout)
{
echo "<li><a href=logout.php >Logout</a></li>";
}
else
{
echo "<li><a href=register.php >Register</a></li>";
echo "<li><a href=login.php >Login</a></li>";
}
?>
回答by deepak kumar
<?php
if(isset($_SESSION['user_id'])) {
echo "<form method='POST' action='".userLogout()."'>"; ?>
<li><button type="submit" name="userlogout" id="logout-button" class="button-logout">LOGOUT</button></li>
<?php } else { ?>
<li><a href="login">LOGIN</a></li>
</form>
<?php }
?>