jQuery 如何使用jQuery从数组中删除特定值
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How to remove specific value from array using jQuery
提问by Elankeeran
I have an array that looks like this: var y = [1, 2, 3];
我有一个看起来像这样的数组： var y = [1, 2, 3];
I would like to remove 2from array y.
我想2从 array 中删除y。
How can I remove a particular value from an array using jQuery? I have tried pop()but that always removes the last element.
如何使用 jQuery 从数组中删除特定值？我试过，pop()但总是删除最后一个元素。
回答by Sarfraz
A working JSFIDDLE
一个有效的JSFIDDLE
You can do something like this:
你可以这样做：
var y = [1, 2, 2, 3, 2]
var removeItem = 2;
y = jQuery.grep(y, function(value) {
return value != removeItem;
});
Result:
结果：
[1, 3]
http://snipplr.com/view/14381/remove-item-from-array-with-jquery/
http://snipplr.com/view/14381/remove-item-from-array-with-jquery/
回答by user113716
With jQuery, you can do a single-line operation like this:
使用 jQuery，您可以执行这样的单行操作：
Example:http://jsfiddle.net/HWKQY/
示例：http : //jsfiddle.net/HWKQY/
y.splice( $.inArray(removeItem, y), 1 );
Uses the native .splice()and jQuery's $.inArray().
使用本机.splice()和 jQuery 的$.inArray().
回答by ddagsan
jQuery.filtermethod is useful. This is available for Arrayobjects.
jQuery.filter方法很有用。这可用于Array对象。
var arr = [1, 2, 3, 4, 5, 5];
var result = arr.filter(function(elem){
return elem != 5;
});//result -> [1,2,3,4]
http://jsfiddle.net/emrefatih47/ar0dhvhw/
http://jsfiddle.net/emrefatih47/ar0dhvhw/
In Ecmascript 6:
在 Ecmascript 6 中：
let values = [1,2,3,4,5];
let evens = values.filter(v => v % 2 == 0);
alert(evens);
回答by vatsal
You can use underscore.js. It really makes things simple.
您可以使用underscore.js。它真的让事情变得简单。
In your case all the code that you will have to write is -
在您的情况下，您必须编写的所有代码是 -
_.without([1,2,3], 2);
and the result will be [1,3].
结果将是 [1,3]。
It reduces the code that you write.
它减少了您编写的代码。
回答by Aamir Afridi
Not a jQuery way but... Why don't use simpler way. Remove 'c' from following array
不是 jQuery 方式，但是...为什么不使用更简单的方式。从以下数组中删除 'c'
var a = ['a','b','c','d']
a.splice(a.indexOf('c'),1);
>["c"]
a
["a", "b", "d"]
You can also use: (Note to myself: Don't modify objects you don't own)
您也可以使用：（请注意：不要修改您不拥有的对象）
Array.prototype.remove = function(v) { this.splice(this.indexOf(v) == -1 ? this.length : this.indexOf(v), 1); }
var a = ['a','b','c'];
a.remove('c'); //value of "a" is now ['a','b']
Adding is simplera.push('c')
添加更简单a.push('c')
回答by praveen d
Remove Item in Array
删除数组中的项目
var arr = ["jQuery", "JavaScript", "HTML", "Ajax", "Css"];
var itemtoRemove = "HTML";
arr.splice($.inArray(itemtoRemove, arr), 1);
回答by yesnik
//This prototype function allows you to remove even array from array
Array.prototype.remove = function(x) {
var i;
for(i in this){
if(this[i].toString() == x.toString()){
this.splice(i,1)
}
}
}
Example of using
使用示例
var arr = [1,2,[1,1], 'abc'];
arr.remove([1,1]);
console.log(arr) //[1, 2, 'abc']
var arr = [1,2,[1,1], 'abc'];
arr.remove(1);
console.log(arr) //[2, [1,1], 'abc']
var arr = [1,2,[1,1], 'abc'];
arr.remove('abc');
console.log(arr) //[1, 2, [1,1]]
To use this prototype function you need to paste it in your code. Then you can apply it to any array with 'dot notation':
要使用此原型函数，您需要将其粘贴到您的代码中。然后你可以将它应用到任何带有“点符号”的数组：
someArr.remove('elem1')
回答by AussieNick
There is no native way to do this in Javascript. You could use a library or write a small function to do this instead: http://ejohn.org/blog/javascript-array-remove/
在 Javascript 中没有本地方法可以做到这一点。您可以使用库或编写一个小函数来执行此操作：http: //ejohn.org/blog/javascript-array-remove/
回答by andrewb
My version of user113716's answer. His removes a value if no match is found, which is not good.
我的 user113716 版本的答案。如果没有找到匹配项，他会删除一个值，这是不好的。
var y = [1, 2, 3]
var removeItem = 2;
var i = $.inArray(removeItem,y)
if (i >= 0){
y.splice(i, 1);
}
alert(y);
This now removes 1 item if a match is found, 0 if no matches are found.
现在，如果找到匹配项，则删除 1 个项目，如果未找到匹配项，则删除 0 个项目。
How it works:
这个怎么运作：
- $.inArray(value, array) is a jQuery function which finds the first index of a
valuein anarray - The above returns -1 if the value is not found, so check that i is a valid index before we do the removal. Removing index -1 means removing the last, which isn't helpful here.
- .splice(index, count) removes
countnumber of values starting atindex, so we just want acountof1
- $ .inArray（值，数组）是一个jQuery函数找到的第一个索引
value中的array - 如果未找到该值，则上述返回 -1，因此在删除之前检查 i 是否为有效索引。删除索引 -1 意味着删除最后一个，这在这里没有帮助。
- .splice（指数计数）删除
count开始值的数量index，所以我们只是想count的1
回答by Vahid Khakestani
You can use .not function like this:
您可以像这样使用 .not 函数：
var arr = [ 1 , 2 , 3 , 5 , 8];
var searchValue = 2;
var newArr = $(arr).not([searchValue]).get();
