Python 查找numpy数组元素的范围
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Finding range of a numpy array elements
提问by khan
I have a NumPy array of size 94 x 155:
我有一个大小为 94 x 155 的 NumPy 数组：
a = [1 2 20 68 210 290..
2 33 34 55 230 340..
.. .. ... ... .... .....]
I want to calculate the range of each row, so that I get 94 ranges in a result. I tried looking for a numpy.rangefunction, which I don't think exists. If this can be done through a loop, that's also fine.
我想计算每一行的范围，以便在结果中得到 94 个范围。我试图寻找一个numpy.range我认为不存在的函数。如果这可以通过循环来完成，那也很好。
I'm looking for something like numpy.mean, which, if we set the axis parameter to 1, returns the mean for each row in the N-dimensional array.
我正在寻找类似的东西numpy.mean，如果我们将轴参数设置为 1，则返回 N 维数组中每一行的平均值。
采纳答案by JoshAdel
I think np.ptpmight do what you want:
我认为np.ptp可能会做你想做的事：
http://docs.scipy.org/doc/numpy/reference/generated/numpy.ptp.html
http://docs.scipy.org/doc/numpy/reference/generated/numpy.ptp.html
r = np.ptp(a,axis=1)
where ris your range array.
r你的范围数组在哪里。
回答by Austin Waters
Try this:
尝试这个：
def range(x, axis=0):
return np.max(x, axis=axis) - np.min(x, axis=axis)
