MySQL 计数在同一个表中,包括零计数值

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/15758201/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-31 17:09:34  来源:igfitidea点击:

MySQL count in same table including zero count values

mysqlcount

提问by Dsp Marian

I have this table structure with data:

我有这个包含数据的表结构:

INSERT INTO `test` (`id`, `email`, `id_user_ref`, `name`) VALUES
(1, '[email protected]', NULL, 'Mike'),
(2, '[email protected]', '1', 'Jhonny'),
(3, '[email protected]', '1', 'Michael'),
(4, '[email protected]', '2', 'Jorhe'),
(5, '[email protected]', '3', 'Mia');

I need to count the id_user_ref for all users with this query:

我需要使用此查询计算所有用户的 id_user_ref :

SELECT id, COUNT(name) AS refNr FROM test GROUP BY id_user_ref
HAVING id_user_ref IS NOT NULL;

This works but the problem is that i need to display all results even if the count result is 0.

这有效,但问题是即使计数结果为 0,我也需要显示所有结果。

I tried several left joins with the same table but without any success.

我在同一张桌子上尝试了几个左连接,但没有成功。

The output should be:

输出应该是:

id  refNr
1    2
2    1
3    1
4    0
5    0

回答by Mahmoud Gamal

Try this:

尝试这个:

SELECT 
  t1.id, 
  IFNULL(COUNT(t2.name), 0) AS refNr 
FROM test AS t1
LEFT JOIN test AS t2 ON t1.id = t2.id_user_ref
GROUP BY t1.id;

SQL Fiddle DEmo

SQL 小提琴演示

This will give you:

这会给你:

| ID | REFNR |
--------------
|  1 |     2 |
|  2 |     1 |
|  3 |     1 |
|  4 |     0 |
|  5 |     0 |

回答by Biswanath

Can you try this ?

你能试试这个吗?

SELECT a.id,
CASE  WHEN b.refNr IS NULL THEN 0
ELSE b.refNr END FROM test a LEFT JOIN
( SELECT id_user_ref, COUNT(name) AS refNr
    FROM test
    WHERE id_user_ref IS NOT NULL
    GROUP BY id_user_ref) b
ON a.id = b.id_user_ref

Sql Demo

Sql 演示