java 如何从文件中读取N行？

How to read N amount of lines from a file?

提问by Hilbis White

I am trying to practice reading text from a file in java. I am little stuck on how I can read N amount of lines, say the first 10 lines in a file and then add the lines in an ArrayList.

我正在尝试练习从 Java 文件中读取文本。我不太了解如何读取 N 行，比如文件中的前 10 行，然后将这些行添加到ArrayList.

Say for example, the file contains 1-100 numbers, like so;

比如说，文件包含 1-100 个数字，像这样；

- 1 
- 2 
- 3 
- 4 
- 5 
- 6 
- 7 
- 8 
- 9 
- 10 
- ....

I want to read the first 5 numbers, so 1,2,3,4,5 and add it to an array list. So far, this is what I have managed to do but I am stuck and have no clue what to do now.

我想读取前 5 个数字，即 1,2,3,4,5 并将其添加到数组列表中。到目前为止，这是我设法做的，但我被卡住了，不知道现在该做什么。

ArrayList<Double> array = new ArrayList<Double>();
InputStream list = new BufferedInputStream(new FileInputStream("numbers.txt"));

for (double i = 0; i <= 5; ++i) {
    // I know I need to add something here so the for loop read through 
    // the file but I have no idea how I can do this
    array.add(i); // This is saying read 1 line and add it to arraylist,
    // then read read second and so on

}

回答by brso05

You could try using a Scanner and a counter:

您可以尝试使用扫描仪和计数器：

     ArrayList<Double> array = new ArrayList<Double>();
     Scanner input = new Scanner(new File("numbers.txt"));
     int counter = 0;
     while(input.hasNextLine() && counter < 10)
     {
         array.add(Double.parseDouble(input.nextLine()));
         counter++;
     }

This should loop through 10 lines adding each to the arraylist as long as there is more inputs in the file.

只要文件中有更多输入，这应该循环 10 行，将每行添加到数组列表中。

回答by WoDoSc

ArrayList<String> array = new ArrayList<String>();
//ArrayList of String (because you will read strings)
BufferedReader reader = null;
try {
    reader = new BufferedReader(new FileReader("numbers.txt")); //to read the file
} catch (FileNotFoundException ex) { //file numbers.txt does not exists
    System.err.println(ex.toString());
    //here you should stop your program, or find another way to open some file
}
String line; //to store a read line
int N = 5; //max number of lines to read
int counter = 0; //current number of lines already read
try {
    //read line by line with the readLine() method
    while ((line = reader.readLine()) != null && counter < N) { 
    //check also the counter if it is smaller then desired amount of lines to read
        array.add(line); //add the line to the ArrayList of strings
        counter++; //update the counter of the read lines (increment by one)
    }
    //the while loop will exit if:
    // there is no more line to read (i.e. line==null, i.e. N>#lines in the file)
    // OR the desired amount of line was correctly read
    reader.close(); //close the reader and related streams
} catch (IOException ex) { //if there is some input/output problem
    System.err.println(ex.toString());
}

回答by Romy

See this How to read a large text file line by line using Java?

请参阅如何使用 Java 逐行读取大型文本文件？

I think this will work:

我认为这会奏效：

BufferedReader br = new BufferedReader(new FileReader(file));
    String line;
    int i = 0;
    while ((line = br.readLine()) != null)
    {
        if (i < 5)
        {
            // process the line.
            i++;
        }
    }
    br.close();

回答by Joop Eggen

List<Integer> array = new ArrayList<>();
try (BufferedReader in = new BufferedReader(
        new InputStreamReader(new FileInputStream("numbers.txt")))) {
    for (int i = 0; i < 5; ++i) { // Loops 5 times
        String line = in.readLine();
        if (line == null) [ // End of file?
            break;
        }
        // line does not contain line-ending.
        int num = Integer.parseInt(line);
        array.add(i);
    }
} // Closes in.
System.out.println(array);

回答by newbieee

ArrayList<Double> myList = new ArrayList<Double>();
int numberOfLinesToRead = 5;
File f = new File("number.txt");
Scanner fileScanner = new Scanner(f);
for(int i=0; i<numberOfLinesToRead; i++){
    myList.add(fileScanner.nextDouble());
}

Make sure you have "numberOfLinesToRead" lines in your file.

确保您的文件中有“numberOfLinesToRead”行。

回答by Chandra

  BufferedReader br = new BufferedReader(new FileReader(file));
  List<String> nlines = IntStream.range(0, hlines)
    .mapToObj(i -> readLine(br)).collect(Collectors.toList());

  String readLine(BufferedReader reader) { 
    try { 
      return reader.readLine();
    } catch (IOException e) { 
      throw new UncheckedIOException(e);
    }
  } 

回答by baumato

You can do this with:

你可以这样做：

try (BufferedReader reader = Files.newBufferedReader(Paths.get("numbers.txt"))) {
    List<String> first10Numbers = reader.lines().limit(10).collect(Collectors.toList());
    // do something with the list here
}

As complete example as JUnit test:

作为 JUnit 测试的完整示例：

public class ReadFirstLinesOfFileTest {

    @Test
    public void shouldReadFirstTenNumbers() throws Exception {
        Path p = Paths.get("numbers.txt");
        Files.write(p, "0\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n".getBytes());

        try (BufferedReader reader = Files.newBufferedReader(Paths.get("numbers.txt"))) {
            List<String> first10Numbers = reader.lines().limit(10).collect(Collectors.toList());
            List<String> expected = Arrays.asList("0", "1", "2", "3", "4", "5", "6", "7", "8", "9");
            Assert.assertArrayEquals(expected.toArray(), first10Numbers.toArray());
        }
    }
}