PHP DateTime 异常和错误处理
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PHP DateTime exception and errors handling
提问by Saturnix
How can I prevent PHP to crash when creating a DateTime object?
创建 DateTime 对象时如何防止 PHP 崩溃？
$in = new DateTime($in);
$out = new DateTime($out);
$inand $outboth comes from a form so they could be anything. I enforce the user to use a calendar and block it to dates with javascript. What if the user can bypass this check?
$in而$out这两个来自一个表格，以便他们可以是任何东西。我强制用户使用日历并使用 javascript 将其阻止到日期。如果用户可以绕过此检查怎么办？
If $in = "anything else other than a date"PHP will crash and block the rendering of the whole page.
如果$in = "anything else other than a date"PHP 会崩溃并阻止整个页面的呈现。
How do I prevent this and just return(0)if PHP is not able to parse the date?
return(0)如果 PHP 无法解析日期，我该如何防止这种情况发生？
回答by faino
Check out the documentation on DateTime(), here's a little snippet:
查看 上的文档DateTime()，这里有一个小片段：
<?php
try {
$date = new DateTime('2000-01-01');
} catch (Exception $e) {
echo $e->getMessage();
exit(1);
}
echo $date->format('Y-m-d');
?>
回答by John Conde
strtotime()will return false if the format is bad so this shouldcatch bad formats.
strtotime()如果格式不好，将返回 false，因此这应该捕获错误的格式。
if (strtotime($in) === false)
{
// bad format
}
回答by Agustin Meriles
What about exception handling?
异常处理呢？
try {
$in = new DateTime($in);
} catch (Exception $e) {
echo $e->getMessage();
return(0);
}
回答by hek2mgl
The DateTimeconstructorwill throw an Exception if the date/time string cannot be parsed. You can catch it. Have a look at the following snippet:
如果无法解析日期/时间字符串，DateTime构造函数将抛出异常。你可以抓住它。看看下面的片段：
try {
$dt = new DateTime('10th - 12th June 2013'); // bad date string
} catch (Exception $e) {
var_dump($e->getMessage());
}
