为什么 sbt 在 build.sbt 工作时使用 Build.scala 报告“未找到：价值 PlayScala”？
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Why does sbt report "not found: value PlayScala" with Build.scala while build.sbt works?
提问by Vikas Raturi
I am creating a multi-module sbt project, with following structure:
我正在创建一个多模块 sbt 项目，具有以下结构：
<root>
----build.sbt
----project
----Build.scala
----plugins.sbt
----common
----LoggingModule
LoggingModuleis a Play Framework project, while commonis a simple Scala project.
LoggingModule是一个 Play Framework 项目，而common是一个简单的 Scala 项目。
In plugins.sbt:
在plugins.sbt：
resolvers += "Typesafe repo" at "http://repo.typesafe.com/typesafe/releases/"
addSbtPlugin("com.typesafe.play" % "sbt-plugin" % "2.3.3")
While I have this in build.sbt, all works fine and it recognises PlayScala:
虽然我有这个build.sbt，但一切正常，它可以识别PlayScala：
name := "Multi-Build"
lazy val root = project.in(file(".")).aggregate(common, LoggingModule).dependsOn(common, LoggingModule)
lazy val common = project in file("common")
lazy val LoggingModule = (project in file("LoggingModule")).enablePlugins(PlayScala)
However as soon I put this in project/Build.scalainstead of `build.sbt' as follows:
但是，一旦我将其放入project/Build.scala而不是`build.sbt'，如下所示：
object RootBuild extends Build {
lazy val root = project.in(file("."))
.aggregate(common, LoggingModule)
.dependsOn(common, LoggingModule)
lazy val common = project in file("common")
lazy val LoggingModule = (project in file("LoggingModule")).enablePlugins(PlayScala)
...//other settings
}
it generates error as:
它生成错误为：
not found: value PlayScala
lazy val LoggingModule = (project in file("LoggingModule")).enablePlugins(PlayScala)
^
How to solve the issue?
如何解决问题？
回答by sjrd
It's just a missing import.
这只是一个缺少的导入。
In .sbtfiles, some things are automatically imported by default: contents of objects extending Plugin, and (>= 0.13.5) autoImportfields in AutoPlugins. This is the case of PlayScala.
在.sbt文件中，默认情况下会自动导入一些内容：对象扩展的内容Plugin，以及s 中的(>= 0.13.5)autoImport字段AutoPlugin。这是 的情况PlayScala。
In a Build.scalafile, normal Scala import rules apply. So you have to import things a bit more explicitly. In this case, you need to import play.PlayScala(or use .enabledPlugins(play.PlayScala)directly).
在Build.scala文件中，适用正常的 Scala 导入规则。所以你必须更明确地导入东西。在这种情况下，您需要import play.PlayScala（或.enabledPlugins(play.PlayScala)直接使用）。
