Java 如何从字符串创建 org.xml.sax.InputSource？
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How do I create an org.xml.sax.InputSource from a String?
提问by Chiggins
I am following a guide, and it gives me the following code:
我正在遵循指南，它给了我以下代码：
InputSource inputSource = new InputSource(new FileInputStream(new File("/path/to/xml/file.xml"))));
What I would like to know, is how I can still create an org.xml.sax.InputSource, but instead of reading the content of a file, use a Stringvariable that I already have.
我想知道的是，我仍然可以创建一个org.xml.sax.InputSource，而不是读取文件的内容，而是使用String我已经拥有的变量。
采纳答案by Gavin H
Use a StringReaderinstead of a FileInputStream.
使用 aStringReader代替 a FileInputStream。
See the documentation for StringReader
请参阅StringReader的文档
example:
例子：
InputSource inputSource = new InputSource( new StringReader( myString ) );
回答by khachik
InputSource inputSource = new InputSource(new java.io.StringReader(string));if it is org.xml.sax.InputSource.
InputSource inputSource = new InputSource(new java.io.StringReader(string));如果是org.xml.sax.InputSource。
