bash 如何使用 grep -e 匹配部分单词？
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How to use grep -e to match partial words?
提问by Flo Bayer
If you use grep like
如果您使用 grep 之类的
grep -rnw '/your/path/to/search/' -e 'n getFoo'
grep wouldn't find a file that contains "function getFoo()".
grep 找不到包含“function getFoo()”的文件。
If you only search for 'getFoo' or else 'function getFoo', grep will find the file that contains the function.
如果您只搜索 'getFoo' 或 'function getFoo'，grep 将找到包含该函数的文件。
So what's the best way to find a file containing part(s) of a string?
那么找到包含字符串部分的文件的最佳方法是什么？
Thanks in advance!
提前致谢！
回答by nyronium
You should remove the -woption which tells grep to only match whole words.
您应该删除-w告诉 grep 只匹配整个单词的选项。
grep -rn '/your/path/to/search/' -e 'n getFoo'
will also search in between word boundaries.
还将在单词边界之间进行搜索。
回答by sjsam
The -wflag causes whole word matches so it clearly what you don't need.
该-w标志会导致整个单词匹配，因此很清楚您不需要什么。
So what's the best way to find a file containing part(s) of a string?
那么找到包含字符串部分的文件的最佳方法是什么？
shopt -s globstar
grep -li 'string to search for' /path/to/search/**
shopt -u globstar
