Java Jaxb + 球衣。跳过生成的json中的空字段
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Jaxb + jersey. Skipping null fields in generated json
提问by ses
I have a code:
我有一个代码：
return Response.status(Status.BAD_REQUEST).entity(errors).build();
Where: Responseis comes from this package: javax.ws.rs.core(jersey 1.9.1);
哪里：Response来自这个包：（javax.ws.rs.core球衣1.9.1）；
Where the errorsis instance of:
其中errors是实例：
@XmlRootElement
public class UserInfoValidationErrors {
@XmlElement String username;
@XmlElement String email;
...
Then I have JSON result like this: {"username":null,"email":"Email is not valid"}
然后我有这样的 JSON 结果： {"username":null,"email":"Email is not valid"}
If there is a way how to avoid having nullthere?
如果有办法如何避免在null那里？
回答by AlexR
Use @XmlElement(nillable = true). At least this works for XML generation, so I believe it should work for JSON as well.
使用@XmlElement(nillable = true). 至少这适用于 XML 生成，所以我相信它也适用于 JSON。
回答by Michael Doyle
If you have Jersey configured to use Hymanson to do it's JSON serialization, you can annotate your model classes with:
如果您已将 Jersey 配置为使用 Hymanson 进行 JSON 序列化，则可以使用以下命令注释模型类：
@JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
@JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
If you want to configure Jersey to use Hymanson, you can update your web.xml as follows:
如果您想配置 Jersey 以使用 Hymanson，您可以按如下方式更新您的 web.xml：
<servlet-name>Jersey</servlet-name>
<servlet-class>
com.sun.jersey.spi.container.servlet.ServletContainer
</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.your.package;org.codehaus.Hymanson.jaxrs</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
