eclipse 如何删除与模式匹配的整行
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How to remove an entire line which matches a pattern
提问by Joe
The following pattern matches an entire line, how do I search and removethese lines. If I leave a space in the replace string, it leaves a blank in that particular line, when I do via eclipse.
以下模式匹配整行，如何搜索和删除这些行。如果我在替换字符串中留下一个空格，当我通过 eclipse 执行时，它会在该特定行中留下一个空白。
^[\t ]*<param name="logic" .*$
回答by El Ronnoco
I don't know anything about eclipse but you may need to include the \nnewline match in order to remove the line completely. Also - is it possible to replace with an empty string as opposed to a space?
我对 eclipse 一无所知，但您可能需要包含\n换行符匹配才能完全删除该行。另外 - 是否可以替换为空字符串而不是空格？
^[\t ]*<param name="logic" .*\n$
回答by Simon D.
To delete the line, you must also remove the line-break, not only the contents of the line. So your Expression should end with \r\n instead of $. Can't try it at the moment, so you will have to experiment yourself for the correct syntax.
要删除该行，您还必须删除换行符，而不仅仅是该行的内容。所以你的表达式应该以 \r\n 而不是 $ 结尾。目前无法尝试，因此您必须自己试验正确的语法。
