Java 无法编写 JSON：未找到类 org.json.JSONObject 的序列化程序，也未发现用于创建 BeanSerializer 的属性
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Could not write JSON: No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer
提问by Sandip Solanki
I have set response as JSON but get this
我已将响应设置为 JSON，但得到了这个
Could not write JSON: No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS)
无法写入 JSON：未找到类 org.json.JSONObject 的序列化程序，也未发现用于创建 BeanSerializer 的属性（为避免异常，请禁用 SerializationFeature.FAIL_ON_EMPTY_BEANS）
@RequestMapping(value = "/customerlist", method = RequestMethod.POST)
public ResponseGenerator getCustomerList() {
ResponseGenerator responseGenerator = new ResponseGenerator();
try {
responseGenerator.setCode(StatusCode.SUCCESS.code);
responseGenerator.setMessage(StatusCode.SUCCESS.message);
responseGenerator.setStatus(ResponseStatus.SUCCESS);
JSONObject data = userService.getUserList();
responseGenerator.setJSONData(data);
return responseGenerator; //error here
} catch (Exception e) {
logger.error("Error while getting Customer List : ", e);
e.printStackTrace();
responseGenerator.setCode(StatusCode.GENERAL_ERROR.code);
responseGenerator.setMessage(StatusCode.GENERAL_ERROR.message);
responseGenerator.setStatus(ResponseStatus.FAIL);
return responseGenerator;
}
}
userService.getUserList():
userService.getUserList():
public JSONObject jsonResp;
public JSONObject getUserList() throws Exception{
jsonResp =new JSONObject();
//List<JSONObject> customers = new ArrayList<JSONObject>();
JSONObject jsonResponse = erpNextAPIClientService.getCustomerList();
//ObjectMapper objectMapper = new ObjectMapper();
//objectMapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
//JSONArray jsonArray = objectMapper.convertValue(jsonResponse.get("data"), JSONArray.class);
JSONArray jsonArray = jsonResponse.getJSONArray("data");
//JSONArray jsonArray =new Gson().fromJson(jsonResponse.get("data").toString(),JSONArray.class);
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject cust = erpNextAPIClientService.getUser(jsonArray.getJSONObject(i).get("name").toString());
JSONObject custAddress =erpNextAPIClientService.getCustomerAddress(jsonArray.getJSONObject(i).get("name").toString());
JSONObject custData = new JSONObject(cust.getString("data"));
JSONObject custAddressData = new JSONObject(custAddress.getString("data"));
custData.accumulate("bill_to_address_line_one",custAddressData.get("address_line1"));
custData.accumulate("bill_to_address_line_two",custAddressData.get("address_line2"));
custData.accumulate("bill_to_city",custAddressData.get("city"));
custData.accumulate("bill_to_state",custAddressData.get("state"));
custData.accumulate("bill_to_zip",custAddressData.get("pincode"));
custData.accumulate("bill_to_country",custAddressData.get("country"));
jsonResp.put("data",custData);
System.out.println(custData.toString());
//customers.add(custData);
}
return jsonResp;
}
采纳答案by Sach141
This will throw an error, as JSONObjectdoes not expose default getter.
Although a workaround can be done to avoid this thing.
这将引发错误，因为JSONObject不会公开 default getter。尽管可以采取一种解决方法来避免这种情况。
You need to change ResponseGeneratorclass to accept Map<String, Object>instead of JSONObject.
Now change this line:
您需要将ResponseGeneratorclass更改为 acceptMap<String, Object>而不是JSONObject. 现在改变这一行：
responseGenerator.setJSONData(data);
to this:
对此：
responseGenerator.setJSONData(data.toMap());
I hope this should work.
我希望这应该有效。
P.S.: My recommendation would be to remove JSONObjectconversion and instead return an Object of actual class,as internally spring uses Hymanson, which is more powerful JSONframework then org.json
PS：我的建议是删除JSONObject转换，而是返回实际类的对象，正如内部 spring 使用的那样Hymanson，这是一个更强大的JSON框架org.json
回答by Pramuditha
Try with this in the entity class. It solved that issue.
在实体类中试试这个。它解决了这个问题。
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
