xcode 以编程方式，如何使用推送转场让应用程序在首先到达屏幕时返回到之前的视图
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Programmatically, how to make an app return to previous view when it got to the screen in the first place using a push segue
提问by Sam Gehly
I am creating an app where if it cannot load a webpage, it displays an error and returns to the previous screen. I am having difficulty getting it to return to the previous screen.
我正在创建一个应用程序，如果它无法加载网页，则会显示错误并返回上一个屏幕。我很难让它返回上一个屏幕。
I am using a push segue to have it go to the screen in the first place.
我首先使用 push segue 让它进入屏幕。
Thank you for your help.
感谢您的帮助。
回答by Chris Trahey
A push segue requires a navigation controller, and with a navigation controller you can use popViewControllerAnimated:
push segue 需要一个导航控制器，并且通过导航控制器你可以使用 popViewControllerAnimated：
[self.navigationController popViewControllerAnimated:YES];
Though many would advocate using delegation for something like this (perhaps even with modal instead of navigation controller).
尽管许多人会提倡使用委托来处理这样的事情（甚至可能使用模式而不是导航控制器）。
