bash /bin/sh: 1: 语法错误：反引号替换中的 EOF
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/bin/sh: 1: Syntax error: EOF in backquote substitution
提问by Vicky
I created a new task in crontab as shown below :
我在 crontab 中创建了一个新任务，如下所示：
*/2 * * * * mongodump --db prodys --out /backup/databases/mongoDatabases/`date +"%m-%d-%y"`
I'm getting following error :
我收到以下错误：
/bin/sh: 1: Syntax error: EOF in backquote substitution
Please help, I don't have any clue whats wrong.
请帮忙，我不知道出了什么问题。
回答by Inian
The problem is that crontreats %as newlines. From crontab POSIX manpage:
问题是它被cron视为%换行符。从crontab POSIX man页面：
Percent-signs (%) in the command, unless escaped with backslash \, will be changed into newline characters, and all data after the first % will be sent to the command as standard input.
命令中的百分号 (%) 除非用反斜杠 \ 转义，否则将更改为换行符，并且第一个 % 之后的所有数据将作为标准输入发送到命令。
Also use Command Substitutionsyntax as $()over the legacy `` syntax as
还使用命令替换语法作为$()传统的 `` 语法作为
You could change your command to something like,
您可以将命令更改为类似的内容，
*/2 * * * * mongodump --db prodys --out /backup/databases/mongoDatabases/$(date +'\%m-\%d-\%y')
