php 不能将标量值用作数组
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Cannot use a scalar value as an array
提问by user947462
I am trying this code:
我正在尝试这个代码：
for ($x = 0; $x < $numCol; $x++) {
for ($i = 0; $i < $numRows; $i++) {
$arr.$x[] = $todas[$i][$x]."\n"; //problem here
}
}
echo $arr0[0];
echo $arr1[0];
...
But i get this warning: Cannot use a scalar value as an array
但我明白了 warning: Cannot use a scalar value as an array
and the echos do nothing. Why ? and what is the solution ?
而回声什么也不做。为什么 ？解决办法是什么？
回答by NullUserException
Here's what you thinkyou want to do. Replace your //problem hereline with:
这就是你认为你想要做的。将您的//problem here线路替换为：
${'arr' . $x}[] = $todas[$x][$i]."\n";
But I would strongly recommend against doing that. Just use your bidimensional array.
但我强烈建议不要这样做。只需使用您的二维数组。
回答by Paul
I think you meant: ${'arr'.$x}[]instead of $arr.$x[].
我想你的意思是：${'arr'.$x}[]而不是$arr.$x[].
$arr.$x[]
Will concatenate the string representation of $arr and $x together so you end up with something like 'Array0'[] = ...instead of $arr0[]
将 $arr 和 $x 的字符串表示连接在一起，所以你最终会得到类似的东西'Array0'[] = ...而不是$arr0[]
回答by crazyjul
When you write $arr.$x[], it is equal to $arr[$x][]
当你写的时候$arr.$x[]，它等于$arr[$x][]
Try replacing your echos by
尝试通过以下方式替换您的回声
echo $arr[0][0];
echo $arr[1][0];
