SQL 运算符不存在:json = json

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/32843213/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-09-01 04:04:18  来源:igfitidea点击:

Operator does not exist: json = json

sqljsonpostgresqlpostgresql-9.4jsonb

提问by Isaac

when I try to select some record from a table

当我尝试从表中选择一些记录时

    SELECT * FROM movie_test WHERE tags = ('["dramatic","women", "political"]'::json)

The sql code cast a error

sql代码抛出错误

LINE 1: SELECT * FROM movie_test WHERE tags = ('["dramatic","women",...
                                        ^
HINT:  No operator matches the given name and argument type(s). You might      need to add explicit type casts.

********** 错误 **********

ERROR: operator does not exist: json = json
SQL 状态: 42883
指导建议:No operator matches the given name and argument type(s). You might need to add explicit type casts.
字符:37

Did I miss something or where I can learn something about this error.

我是不是错过了什么,或者我可以在哪里了解这个错误。

回答by klin

You cannot compare json values. You can compare text values instead:

您无法比较 json 值。您可以比较文本值:

SELECT * 
FROM movie_test 
WHERE tags::text = '["dramatic","women","political"]'

Note however that values of type jsonare stored as text in a format in which they are given. Thus the result of comparison depends on whether you consistently apply the same format:

但是请注意,type 的值以json它们给出的格式存储为文本。因此,比较的结果取决于您是否始终应用相同的格式:

SELECT 
    '["dramatic" ,"women", "political"]'::json::text =  
    '["dramatic","women","political"]'::json::text      -- yields false!

In Postgres 9.4+ you can solve this problem using type jsonb, which is stored in a decomposed binary format. Values of this type can be compared:

在 Postgres 9.4+ 中,您可以使用 type 解决这个问题jsonb,它以分解的二进制格式存储。可以比较这种类型的值:

SELECT 
    '["dramatic" ,"women", "political"]'::jsonb =  
    '["dramatic","women","political"]'::jsonb           -- yields true

so this query is much more reliable:

所以这个查询更可靠:

SELECT * 
FROM movie_test 
WHERE tags::jsonb = '["dramatic","women","political"]'::jsonb

Read more about JSON Types.

阅读有关JSON 类型的更多信息。