PHP：在 unset() 之后重新排列数组
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PHP: Reorder arrays after unset()
提问by Zebra
There are 2 functions involved.
涉及2个函数。
- Search array items for a given string
- unset() array item if string not found
- 搜索给定字符串的数组项
- 如果未找到字符串，则 unset() 数组项
$array = array("first", "second", "third", "fourth");
foreach($array as $i=> $string) {
if(stristr($string, "e")) {
unset($array[$i]);
}
}
secondis the array item with the character 'e'. If its unset, $array[1]would be left empty:
second是带有字符“e”的数组项。如果它的unset,$array[1]将留空：
$array[0] = "first"
$array[1] = ""
$array[2] = "third"
$array[3] = "fourth"
I want $array[1]to be removed from the array (like in array_shift()), so that thirdtakes the place of secondand fourththe place of third:
我想$array[1]从数组中删除（如 in array_shift()），以便third代替second和fourth的位置third：
$array[0] = "first"
$array[1] = "third"
$array[2] = "fourth"
回答by Matthew
$array = array_values($array);
回答by 538ROMEO
I think the best solution I've found is :
我认为我找到的最佳解决方案是：
Solution 1
解决方案1
if you just want to remove just one element :
如果您只想删除一个元素：
array_splice($array,1,1); // all keys will be reindexed from 0
where the second and third parameters are offset (key) and length (how many to remove)
其中第二个和第三个参数是偏移量（键）和长度（要删除多少）
Solution 2
解决方案2
The best to remove multiple keys : use array_filter()to remove all empty strings and falsey value from the array then array_splice()to reorder :
最好删除多个键：用于array_filter()从数组中删除所有空字符串和 falsey 值，然后array_splice()重新排序：
array_splice(array_filter($array), 0, 0);
