C语言 将 strcpy 与 C 中的字符串数组一起使用
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Using strcpy with a string array in C
提问by Adam
I have a character array defined as follows: char *c[20];
I'm trying to do: strcpy(c[k], "undefined);but it's not working
我有一个定义如下的字符数组：char *c[20];
我正在尝试：strcpy(c[k], "undefined);但它不起作用
I've also tried defining it as char c[20][70]with no luck.
我也尝试将其定义为char c[20][70]没有运气。
Edit: I actually know it's an array of character arrays, I need it like that.
编辑：我实际上知道它是一个字符数组数组，我需要它。
回答by Seth Carnegie
That's not a character array; that's an array of character pointers. Remove the *to make it a character array:
那不是字符数组；这是一个字符指针数组。删除*以使其成为字符数组：
char c[20];
Then you can use strcpy:
然后你可以使用strcpy：
strcpy(c, "undefined");
If you really did want an array of character arrays, you'll have to do what you said you tried:
如果您确实想要一个字符数组数组，则必须按照您所说的进行操作：
// array that holds 20 arrays that can hold up to 70 chars each
char c[20][70];
// copy "undefined" into the third element
strcpy(c[2], "undefined");
The problem could have been you're missing the closing ", I don't know if that was a paste error though. Or, the problem could have been that you're using kwithout defining it, we can't know without seeing the error message you get.
问题可能是您错过了结束语"，但我不知道这是否是粘贴错误。或者，问题可能是您在使用时k没有定义它，我们无法在没有看到您收到的错误消息的情况下知道。
If you want to set them all to that string, then just loop over them:
如果要将它们全部设置为该字符串，则只需循环它们：
char c[20][70];
int i;
for (i = 0; i < 20; ++i)
strcpy(c[i], "undefined");
回答by Miguel
If what you want is to have 20 strings of 70 chars each then your second option should work:
如果您想要的是每个 70 个字符的 20 个字符串，那么您的第二个选项应该可以工作：
char c[20][70];
for (int k = 0; k < 20; k++)
strcpy(c[k], "undefined");
The char *c[20]definition is incorrect because you are just defining an array of 20 pointers, and the pointers are not initialized. You could make it work in this way:
该char *c[20]定义不正确，因为你只是定义的20个指针数组，指针不会被初始化。你可以让它以这种方式工作：
char *c[20];
for (int k = 0; k < 20; k++) {
c[k] = malloc(70);
strcpy(c[k], "undefined");
}
// then when you are done with these strings
for (int k = 0; k < 20; k++)
free(c[k]);
