Java 使用替换替换字符串中的字母表？
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Replace alphabet in a string using replace?
提问by Arch1tect
I'm wondering if I can use string.replace()to replace all alphabets in a string?
我想知道是否可以string.replace()用来替换字符串中的所有字母？
String sentence = "hello world! 722"
String str = sentence.replace("what to put here", "@");
//now str should be "@@@@@ @@@@@! 722"
In other words, how do I represent alphabetic characters?
换句话说，我如何表示字母字符？
Alternatives are welcomed too, unless too long.
替代方案也受到欢迎，除非时间太长。
采纳答案by acdcjunior
Java's String#replaceAlltakes a regex string as argument. Tha being said, [a-ZA-Z]matches any char from ato z(lowercase) and Ato Z(uppercase) and that seems to be what you need.
JavaString#replaceAll将正则表达式字符串作为参数。话虽如此，[a-ZA-Z]匹配从ato z（小写）和Ato Z（大写）的任何字符，这似乎是您所需要的。
String sentence = "hello world! 722";
String str = sentence.replaceAll("[a-zA-Z]", "@");
System.out.println(str); // "@@@@@ @@@@@! 722"
See demohere.
回答by Maroun
Use String#replaceAllthat takes a Regex:
使用String#replaceAll需要正则表达式：
str = str.replaceAll("[a-zA-Z]", "@");
Note that String#replacetakes a String as argument and not a Regex. If you still want to use it, you should loop on the String char-by-char and check whether this char is in the range [a-z] or [A-Z] and replaceit with @. But if it's not a homework and you can use replaceAll, use it :)
请注意，String#replace将 String 作为参数而不是Regex。如果你还想使用它，你应该逐个字符地循环字符串并检查这个字符是否在 [az] 或 [AZ] 范围内，并将其替换为@. 但如果它不是家庭作业并且您可以使用replaceAll，请使用它:)
回答by Michael
You can use the following (regular expression):
您可以使用以下（正则表达式）：
String test = "hello world! 722";
System.out.println(test);
String testNew = test.replaceAll("(\p{Alpha})", "@");
System.out.println(testNew);
You can read all about it in here: http://docs.oracle.com/javase/tutorial/essential/regex/index.html
您可以在这里阅读所有相关信息：http: //docs.oracle.com/javase/tutorial/essential/regex/index.html
