Java 如何将 String 对象（包含 XML）“转换”为现有 JSP 页面上的元素
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How to 'transform' a String object (containing XML) to an element on an existing JSP page
提问by Lycana
Currently, I have a String object that contains XML elements:
目前，我有一个包含 XML 元素的 String 对象：
String carsInGarage = garage.getCars();
I now want to pass this String as an input/stream source (or some kind of source), but am unsure which one to choose and how to implement it.
我现在想将此字符串作为输入/流源（或某种源）传递，但不确定选择哪个以及如何实现它。
Most of the solutions I have looked at import the package: javax.xml.transform and accept a XML file (stylerXML.xml) and output to a HTML file (outputFile.html) (See code below).
我看过的大多数解决方案都导入包：javax.xml.transform 并接受一个 XML 文件（stylerXML.xml）并输出到一个 HTML 文件（outputFile.html）（见下面的代码）。
try
{
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer(new StreamSource("styler.xsl"));
transformer.transform(new StreamSource("stylerXML.xml"), new StreamResult(new FileOutputStream("outputFile.html")));
}
catch (Exception e)
{
e.printStackTrace();
}
I want to accept a String object and output (using XSL) to a element within an existing JSP page. I just don't know how to implement this, even having looked at the code above.
我想接受一个 String 对象并输出（使用 XSL）到现有 JSP 页面中的一个元素。我只是不知道如何实现这一点，即使查看了上面的代码。
Can someone please advise/assist. I have searched high and low for a solution, but I just can't pull anything out.
有人可以请建议/协助。我一直在寻找解决方案，但我无法拿出任何东西。
采纳答案by bruno conde
Use a StringReaderand a StringWriter:
使用 aStringReader和 a StringWriter：
try {
StringReader reader = new StringReader("<xml>blabla</xml>");
StringWriter writer = new StringWriter();
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer(
new javax.xml.transform.stream.StreamSource("styler.xsl"));
transformer.transform(
new javax.xml.transform.stream.StreamSource(reader),
new javax.xml.transform.stream.StreamResult(writer));
String result = writer.toString();
} catch (Exception e) {
e.printStackTrace();
}
回答by jelovirt
If at some point you want the source to contain more than just a single string, or you don't want to generate the XML wrapper element manually, create a DOM document that contains your source and pass it to the transformer using a DOMSource.
如果在某些时候您希望源代码不仅仅包含单个字符串，或者您不想手动生成 XML 包装器元素，请创建一个包含源代码的 DOM 文档并使用DOMSource将其传递给转换器。
回答by Teejay
This worked for me.
这对我有用。
String str = "<my>xml</my>"
StreamSource src = new StreamSource(new StringReader(str));
ByteArrayOutputStream baos = new ByteArrayOutputStream();
Result res = new StreamResult(baos);
transformer.transform(src, res);
