C# 当返回类型为 ActionResult 时，如何对操作进行单元测试？
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How to unit-test an action, when return type is ActionResult?
提问by Abhijeet
I have written unit test for following action.
我已经为以下操作编写了单元测试。
[HttpPost]
public ActionResult/*ViewResult*/ Create(MyViewModel vm)
{
if (ModelState.IsValid)
{
//Do something...
return RedirectToAction("Index");
}
return View(vm);
}
Test method can access Modelproperties, only when return type is ViewResult. In above code, I have used RedirectToActionso return type of this action can not be ViewResult.
测试方法可以访问Model属性，只有当返回类型为ViewResult. 在上面的代码中，我使用了RedirectToAction所以这个动作的返回类型不能是ViewResult.
In such scenario how do you unit-test an action?
在这种情况下，您如何对操作进行单元测试？
采纳答案by Péter
So here is my little example:
所以这是我的小例子：
public ActionResult Index(int id)
{
if (1 != id)
{
return RedirectToAction("asd");
}
return View();
}
And the tests:
和测试：
[TestMethod]
public void TestMethod1()
{
HomeController homeController = new HomeController();
ActionResult result = homeController.Index(10);
Assert.IsInstanceOfType(result,typeof(RedirectToRouteResult));
RedirectToRouteResult routeResult = result as RedirectToRouteResult;
Assert.AreEqual(routeResult.RouteValues["action"], "asd");
}
[TestMethod]
public void TestMethod2()
{
HomeController homeController = new HomeController();
ActionResult result = homeController.Index(1);
Assert.IsInstanceOfType(result, typeof(ViewResult));
}
Edit:
Once you verified that the result type is ViewResut you can cast to it:
编辑：
验证结果类型为 ViewResut 后，您可以将其转换为：
ViewResult vResult = result as ViewResult;
if(vResult != null)
{
Assert.IsInstanceOfType(vResult.Model, typeof(YourModelType));
YourModelType model = vResult.Model as YourModelType;
if(model != null)
{
//...
}
}
回答by Esteban Chi
Please note that
请注意
Assert.IsInstanceOfType(result,typeof(RedirectToRouteResult));
has been deprecated.
已被弃用。
The new syntax is
新语法是
Assert.That(result, Is.InstanceOf<RedirectToRouteResult>());
回答by ANKIT SINGH
Try this code:
试试这个代码：
dynamic result=objectController.Index();
Assert.AreEqual("Index",result.ViewName);
