pandas 为什么会出现错误 - 无法连接非 NDFrame 对象
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Why is it giving the error-cannot concatenate a non-NDFrame object
提问by VaibhavSka
The fill function is to fill all the non-available data in titanic with the average age of that particular class of passengers
填充功能是用该特定类别乘客的平均年龄填充泰坦尼克号中所有不可用的数据
titanic['Age']=titanic[['Age','Pclass']].apply(fill,axis=1)
sex=pd.get_dummies(titanic['Sex'],drop_first=True)
embarked=pd.get_dummies(titanic['Embarked'],drop_first=True)
titanic.drop(['Cabin','Embarked'],axis=1,inplace=True)
titanic.dropna(inplace=True)
titanic=pd.concat(['titanic','sex','embarked'],axis=1)
回答by Bharath
pd.concat expects you to give list of dataframe as parameter not a list of strings. Change your code to
pd.concat 期望您将数据帧列表作为参数而不是字符串列表。将您的代码更改为
titanic=pd.concat([titanic,sex,embarked],axis=1)
回答by Rayhane Mama
I think you mean:
我想你的意思是：
titanic=pd.concat([titanic,sex,embarked],axis=1)
instead of:
代替：
titanic=pd.concat(['titanic','sex','embarked'],axis=1)
A side note however:
If you're just trying to drop NaNvalues and get dummies you can do it on the original dataframe without having to use pandas.concat.
但是，附带说明：
如果您只是想删除NaN值并获取虚拟对象，则可以在原始数据帧上进行操作，而无需使用pandas.concat。
example:
例子：
titanic = pd.get_dummies(titanic)
and just drop NaN values with dataframe.dropna:
只需使用dataframe.dropna删除 NaN 值：
titanic.dropna(inplace=True)
Hope this was helpful.
希望这是有帮助的。
