java 我怎么能比较java中的颜色？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/15262258/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
how could i compare colors in java?
提问by Ryan Maddox
im trying to make a random color generator but i dont want similar colors to show up in the arrayList
我正在尝试制作一个随机颜色生成器，但我不希望在 arrayList 中显示类似的颜色
public class RandomColorGen {
public static Color RandColor() {
Random rand = new Random();
float r = rand.nextFloat();
float g = rand.nextFloat();
float b = rand.nextFloat();
Color c = new Color(r, g, b, 1);
return c;
}
public static ArrayList<Color> ColorList(int numOfColors) {
ArrayList<Color> colorList = new ArrayList<Color>();
for (int i = 0; i < numOfColors; i++) {
Color c = RandColor();
if(similarcolors){
dont add
}
colorList.add(c);
}
return colorList;
}
}
I'm really confused please help :)
我真的很困惑请帮忙:)
回答by StarPinkER
Implement a similarTo() method in Color class.
在 Color 类中实现一个 similarTo() 方法。
Then use:
然后使用：
public static ArrayList<Color> ColorList(int numOfColors) {
ArrayList<Color> colorList = new ArrayList<Color>();
for (int i = 0; i < numOfColors; i++) {
Color c = RandColor();
boolean similarFound = false;
for(Color color : colorList){
if(color.similarTo(c)){
similarFound = true;
break;
}
}
if(!similarFound){
colorList.add(c);
}
}
return colorList;
}
To implement the similarTo:
实现similarTo：
Take a look at Color similarity/distance in RGBA color spaceand finding similar colors programatically. A simple approach can be:
看看RGBA 颜色空间中的颜色相似性/距离并以编程方式找到相似的颜色。一个简单的方法可以是：
((r2 - r1)2+ (g2 - g1)2+ (b2 - b1)2)1/2
((r2 - r1) 2+ (g2 - g1) 2+ (b2 - b1) 2) 1/2
And:
和：
boolean similarTo(Color c){
double distance = (c.r - this.r)*(c.r - this.r) + (c.g - this.g)*(c.g - this.g) + (c.b - this.b)*(c.b - this.b)
if(distance > X){
return true;
}else{
return false;
}
}
However, you should find your X according to your imagination of similar.
然而，你应该根据你的想象找到你的X相似。
回答by Seikon
I tried this and it worked very well:
我试过这个，效果很好：
Color c1 = Color.WHITE;
Color c2 = new Color(255,255,255);
if(c1.getRGB() == c2.getRGB())
System.out.println("true");
else
System.out.println("false");
}
The getRGBfunction returns an int value with the sum of Red Blue and Green, so we are comparing integers not objects.
该getRGB函数返回一个包含红蓝绿总和的 int 值，因此我们比较的是整数而不是对象。
