Javascript 为什么 Firebug 说 toFixed() 不是函数？
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Why does Firebug say toFixed() is not a function?
提问by Evik James
I am using jQuery 1.7.2 and jQuery UI 1.9.1. I am using the code below within a slider. (http://jqueryui.com/slider/)
我使用 jQuery 1.7.2 和 jQuery UI 1.9.1。我在滑块中使用下面的代码。(http://jqueryui.com/slider/)
I have a function that should test two values and depending on the difference between the two values reformat them (to the appropriate decimal place). If the difference is greater than 10, I will parse out the integer. If the difference is greater than 5, it should keep one decimal. Everything else, I will keep two decimals.
我有一个函数应该测试两个值，并根据两个值之间的差异重新格式化它们（到适当的小数位）。如果差值大于10，我会解析出整数。如果差值大于5，则保留一位小数。其他的，我会保留两位小数。
When I enter two values that have a difference that is ten or less, I use the toFixed() function. And, in Firebug, I see an error:
当我输入两个相差不超过 10 的值时，我使用 toFixed() 函数。而且，在 Firebug 中，我看到一个错误：
TypeError: Low.toFixed is not a function
Low = Low.toFixed(2);
Is there something simple that I am doing wrong?
有什么简单的事情我做错了吗？
Here is my code:
这是我的代码：
var Low = $SliderValFrom.val(),
High = $SliderValTo.val();
// THE NUMBER IS VALID
if (isNaN(Low) == false && isNaN(High) == false) {
Diff = High - Low;
if (Diff > 10) {
Low = parseInt(Low);
High = parseInt(High);
} else if (Diff > 5) {
Low = Low.toFixed(1);
High = High.toFixed(1);
} else {
Low = Low.toFixed(2);
High = High.toFixed(2);
}
}
回答by jeremy
toFixedisn't a method of non-numeric variable types. In other words, Lowand Highcan't be fixed because when you get the value of something in Javascript, it automatically is set to a string type. Using parseFloat()(or parseInt()with a radix, if it's an integer) will allow you to convert different variable types to numbers which will enable the toFixed()function to work.
toFixed不是非数字变量类型的方法。换句话说，Low并且High无法修复，因为当您在 Javascript 中获取某些内容的值时，它会自动设置为字符串类型。使用parseFloat()（或parseInt()使用基数，如果它是整数）将允许您将不同的变量类型转换为数字，这将使toFixed()函数能够工作。
var Low = parseFloat($SliderValFrom.val()),
High = parseFloat($SliderValTo.val());
回答by Naftali aka Neal
That is because Lowis a string.
那是因为Low是一个字符串。
.toFixed()only works with a number.
.toFixed()只适用于一个数字。
Try doing:
尝试做：
Low = parseFloat(Low).toFixed(..);
回答by Jo?o Pimentel Ferreira
Lowis a string.
Low是一个字符串。
.toFixed()only works with a number.
.toFixed()只适用于一个数字。
A simple way to overcome such problem is to use type coercion:
克服此类问题的一个简单方法是使用类型强制：
Low = (Low*1).toFixed(..);
The multiplication by 1 forces to code to convert the string to number and doesn't change the value. JSFiddle code here.
乘以 1 会强制编码将字符串转换为数字并且不会更改值。JSFiddle 代码在这里。
回答by Idan
You need convert to number type:
您需要转换为数字类型：
(+Low).toFixed(2)
回答by Harry_pb
In a function, use as
在函数中，用作
render: function (args) {
if (args.value != 0)
return (parseFloat(args.value).toFixed(2));
},
