Android 以编程方式创建 TableLayout
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Create TableLayout programmatically
提问by mark
I'm trying to create a TableLayout programatically. It just won't work. The same layout in an xml file works though. This is what I have:
我正在尝试以编程方式创建一个 TableLayout。它只是行不通。xml 文件中的相同布局虽然有效。这就是我所拥有的：
public class MyTable extends TableLayout
{
public MyTable(Context context) {
super(context);
setLayoutParams(new TableLayout.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
TableRow row = new TableRow(context);
row.setLayoutParams(new TableRow.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
Button b = new Button(getContext());
b.setText("hello");
b.setLayoutParams(new LayoutParams(TableRow.LayoutParams.FILL_PARENT, TableRow.LayoutParams.WRAP_CONTENT));
row.addView(b);
addView(row)
}
}
...
// In main activity:
MyTable table = new MyTable(this);
mainLayout.addView(table);
When I run this, I don't get a crash, but nothing appears. If I get rid of the TableRow instance, at least the button does appear as a direct child of the TableLayout. What am I doing wrong?
当我运行它时，我没有崩溃，但什么也没出现。如果我摆脱了 TableRow 实例，至少按钮确实显示为 TableLayout 的直接子项。我究竟做错了什么？
回答by Grigori A.
Just to make the answer more clear:
只是为了让答案更清楚：
TableLayout.LayoutParams tableParams = new TableLayout.LayoutParams(TableLayout.LayoutParams.WRAP_CONTENT, TableLayout.LayoutParams.WRAP_CONTENT);
TableRow.LayoutParams rowParams = new TableRow.LayoutParams(TableRow.LayoutParams.WRAP_CONTENT, TableRow.LayoutParams.WRAP_CONTENT);
TableLayout tableLayout = new TableLayout(context);
tableLayout.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT, LinearLayout.LayoutParams.WRAP_CONTENT));// assuming the parent view is a LinearLayout
TableRow tableRow = new TableRow(context);
tableRow.setLayoutParams(tableParams);// TableLayout is the parent view
TextView textView = new TextView(context);
textView.setLayoutParams(rowParams);// TableRow is the parent view
tableRow.addView(textView);
Explanation
When you call setLayoutParams, you are supposed to pass the LayoutParamsof the parent view
说明
当您调用时setLayoutParams，您应该传递LayoutParams父视图的
回答by mark
It turns out I needed to specify TableRowLayout, TableLayout etc for the layout params, otherwise the table just won't show!
结果我需要为布局参数指定 TableRowLayout、TableLayout 等，否则表格将不会显示！
回答by clotilde
A good solution is to inflate layout files for each instance of row you want to create. See this post : How to duplicate Views to populate lists and tables?
一个好的解决方案是为要创建的每个行实例扩充布局文件。请参阅这篇文章：如何复制视图以填充列表和表格？
回答by ericn
Your problem is at this line:
你的问题是在这一行：
b.setLayoutParams(new LayoutParams(TableRow.LayoutParams.FILL_PARENT, TableRow.LayoutParams.WRAP_CONTENT));
You need to change LayoutParamsto TableRow.LayoutParams:
您需要更改LayoutParams为TableRow.LayoutParams：
b.setLayoutParams(new TableRow.LayoutParams(TableRow.LayoutParams.FILL_PARENT, TableRow.LayoutParams.WRAP_CONTENT));
回答by John Moses
For me, to get mine I had to call addContentView().
对我来说，为了得到我的，我不得不打电话addContentView()。
