vb.net 正则表达式删除所有数字和所有点
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Regular Expression to remove all numbers and all dots
提问by eawedat
I have this code in VB.NET :
我在 VB.NET 中有这个代码：
MessageBox.Show(Regex.Replace("Example 4.12.0.12", "\d", ""))
It removes/extracts numbers
它删除/提取数字
I want also to remove dots
我也想删除点
so I tried
所以我试过了
MessageBox.Show(Regex.Replace("Example 4.12.0.12", "\d\.", ""))
but it keeps the numbers.
但它保留了数字。
how to remove both (numbers & dots) from the string ?
如何从字符串中同时删除（数字和点）？
thanks.
谢谢。
回答by pmcoltrane
Try using a character group:
尝试使用字符组：
MessageBox.Show(Regex.Replace("Example 4.12.0.12", "[\d\.]", ""))
I'll elaborate since I inadvertently posted essentially the same answer as Steven.
我会详细说明，因为我无意中发布了与史蒂文基本相同的答案。
Given the input "Example 4.12.0.12"
鉴于输入 "Example 4.12.0.12"
"\d"matches digits, so the replacement gives"Example ...""\d\."matches a digit followed by a dot, so the replacement gives"Example 112""[\d.]"matches anything that is a digit or a dot. As Steven said, it's not necessary to escape the dot inside the character group.
"\d"匹配数字，所以替换给出"Example ...""\d\."匹配一个数字后跟一个点，所以替换给出"Example 112""[\d.]"匹配任何数字或点。正如史蒂文所说，没有必要对字符组内的点进行转义。
回答by Steven Doggart
You need to create a character group using square brackets, like this:
您需要使用方括号创建一个字符组，如下所示：
MessageBox.Show(Regex.Replace("Example 4.12.0.12", "[\d.]", ""))
A character group means that any one of the characters listed in the group is considered a valid match. Notice that, within the character group, you don't need to escape the .character.
字符组意味着组中列出的任何一个字符都被视为有效匹配。请注意，在字符组内，您不需要对.字符进行转义。
