Javascript 删除最后一个反斜杠后的所有内容
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Remove everything after last backslash
提问by InGeek
var t = "\some\route\here"
var t = "\some\route\here"
I need "\some\route" from it.
我需要它的“\some\route”。
Thank you.
谢谢你。
回答by Reinstate Monica Cellio
You need lastIndexOfand substr...
你需要lastIndexOf和substr...
var t = "\some\route\here";
t = t.substr(0, t.lastIndexOf("\"));
alert(t);
Also, you need to double up \chars in strings as they are used for escaping special characters.
此外，您需要将\字符串中的字符加倍，因为它们用于转义特殊字符。
UpdateSince this is regularly proving useful for others, here's a snippet example...
更新由于这经常被证明对其他人有用，这里有一个片段示例......
// the original string
var t = "\some\route\here";
// remove everything after the last backslash
var afterWith = t.substr(0, t.lastIndexOf("\") + 1);
// remove everything after & including the last backslash
var afterWithout = t.substr(0, t.lastIndexOf("\"));
// show the results
console.log("before : " + t);
console.log("after (with \) : " + afterWith);
console.log("after (without \) : " + afterWithout);回答by ic3b3rg
As stated in @Archer's answer, you need to double up on the backslashes. I suggest using regex replace to get the string you want:
正如@Archer 的回答中所述，您需要将反斜杠加倍。我建议使用正则表达式替换来获取你想要的字符串：
var t = "\some\route\here";
t = t.replace(/\[^\]+$/,"");
alert(t);
回答by isuru
Using JavaScript you can simply achieve this. Remove everything after last "_" occurance.
使用 JavaScript，您可以简单地实现这一点。删除最后一次出现“_”后的所有内容。
var newResult = t.substring(0, t.lastIndexOf("_") );
