将 Java 控制台应用程序作为守护程序运行（后台）
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Run Java console app as a daemon (background)
提问by aleroot
I've developed a Java console application that when start, open a console window and remain in foreground, i want to start that application in background .
我开发了一个 Java 控制台应用程序，它在启动时打开一个控制台窗口并保持在前台，我想在后台启动该应用程序。
Now i launch the application by this command line :
现在我通过这个命令行启动应用程序：
java -jar myapp.jar
Is there a way to achieve this behaviour ? It's enough change the command line parameter or i need to do some change on my code ?
有没有办法实现这种行为？更改命令行参数就足够了，或者我需要对我的代码进行一些更改？
采纳答案by Steve Brisk
The answer is operating system dependent.
答案取决于操作系统。
*nix: <your command> &
Windows: (opens a new console): start <your command>
Windows: (doesn't open a new console): start /b <your command>
回答by Amir Raminfar
If you are doing this in anything unix based then you can append & to the end which will spawn a new thread and keept it running in the background.
如果您在任何基于 unix 的系统中执行此操作，那么您可以将 & 附加到末尾，这将产生一个新线程并使其在后台运行。
java -jar myapp.jar &
回答by sarnold
If you really just want it to run in the background, java -jar myapp.jar &will do the job. That way, it'll still die when the shell closes, but you can keep using your shell.
如果你真的只是想让它在后台运行，java -jar myapp.jar &就可以完成这项工作。这样，当 shell 关闭时它仍然会死，但你可以继续使用你的 shell。
If you really want it run as a daemon, nohup java -jar myapp.jar &will do the job. That way, it'll continue to live when the shell closes.
如果您真的希望它作为守护进程运行，nohup java -jar myapp.jar &它将完成这项工作。这样，当外壳关闭时它会继续存在。
If you want this to be reliable, you can prepare an init script or upstart job definition, or run it via Vixie cron(8)@rebootspecifier to make it start at boot.
如果您希望它可靠，您可以准备一个 init 脚本或upstart 作业定义，或者通过 Vixiecron(8)@reboot说明符运行它以使其在启动时启动。
回答by Jim
Given that you're using Windows, you might consider Java Service Wrapper. I have used it on a project in the past.
鉴于您使用的是 Windows，您可能会考虑Java Service Wrapper。我过去在一个项目中使用过它。
