Java 如何从我的字符串中删除一些字符
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How do I remove some characters from my String
提问by code511788465541441
i want to remove all of the following chars from my string
我想从我的字符串中删除以下所有字符
">[],-"
">[],-"
at the moment im doing this. but there must be a more efficient way
目前我正在这样做。但必须有更有效的方法
newString = myString.replace(">","").replace("[","").replace("]","")....
采纳答案by Karl Knechtel
Use a regex that describes all the characters you want to replace, with the method that replaces everything matching the regex:
使用描述要替换的所有字符的正则表达式，以及替换与正则表达式匹配的所有字符的方法：
newString = myString.replaceAll("[<>\[\],-]", "");
(edited: I don't think <>are supposed to be escaped, actually. And I forgot to double up the backslashes since they'll be interpreted twice: once by the Java compiler, and again by the regular expression engine.)
（编辑：我认为<>实际上不应该被转义。而且我忘记将反斜杠加倍，因为它们将被解释两次：一次由 Java 编译器解释，另一次由正则表达式引擎解释。）
回答by Darron
newString = myString.replaceAll("[>\[\],-]", "");
The backslashes are to escape the '[' because the first argument is actually a regular expression.
反斜杠是为了转义“[”，因为第一个参数实际上是一个正则表达式。
回答by Jonathan Wood
You could loop through each character, appending them one by one to a StringBuilder() unless they match one of the characters you are removing.
您可以遍历每个字符，将它们一个一个地附加到 StringBuilder() ，除非它们与您要删除的字符之一匹配。
But I'm not sure that'd be a whole lot faster.
但我不确定那会快很多。
回答by darioo
newString = myString.replaceAll("[>\[\],-]", "");
回答by Kurt Kaylor
Using the replace / replaceAll methods causes a new Pattern to be compiled each time. So if you are doing this multiple times I would strongly suggest either looping through the characters or creating a single regular expression to use repeatedly.
使用 replace / replaceAll 方法会导致每次编译一个新的 Pattern。因此，如果您多次执行此操作，我强烈建议您循环遍历字符或创建单个正则表达式以重复使用。
回答by Andreas Dolk
More efficient performace-wise: yes. You can't "delete" chars from a String so you have t create a new one anyway. Consider a switch/case based solution:
更高效的性能：是的。您不能从字符串中“删除”字符，因此无论如何您都不必创建一个新字符。考虑基于 switch/case 的解决方案：
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
switch(s.getCharAt(i)) {
case '>':
case '[':
case ']':
case ',':
case '-': break;
default: sb.append(s.getCharAt(i));
}
}
s = sb.toString();
回答by codaddict
You can use the replaceAllmethod of the Stringclass.
您可以使用类的replaceAll方法String。
You can form a character class consisting of the characters you want to delete. And the replacement string will be empty string "".
您可以形成一个由您要删除的字符组成的字符类。并且替换字符串将为空字符串""。
But the characters you want to delete which you'll be putting in the character class might be regex meta-characters and hence need to be escaped. You can manually escape them as many answers show, alternatively you can use the Pattern.quote()method.
但是您要删除的字符可能是正则表达式元字符，因此需要对其进行转义。您可以像许多答案显示的那样手动转义它们，或者您可以使用该Pattern.quote()方法。
String charToDel = ">[],-";
String pat = "[" + Pattern.quote(charToDel) + "]";
String str = "a>b[c]d,e-f";
str = str.replaceAll(pat,"");
