C++ 如何使用变量名创建ofstream文件？
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时间：2020-08-27 21:09:08 来源:igfitidea点击:
How to create ofstream file with name of variable?
提问by user2531700
char NAME[256];
cin.getline (NAME,256);
ofstream fout("NAME.txt"); //NAME???????
What i need to do to create file with NAME name?
我需要做什么来创建具有 NAME 名称的文件？
回答by Kerrek SB
Like this:
像这样：
#include <string>
#include <fstream>
std::string filename;
std::getline(std::cin, filename);
std::ofstream fout(filename);
In older versions of C++ the last line needs to be:
在旧版本的 C++ 中，最后一行需要是：
std::ofstream fout(filename.c_str());
回答by moooeeeep
You could try:
你可以试试：
#include <string>
#include <iostream>
#include <fstream>
int main() {
// use a dynamic sized buffer, like std::string
std::string filename;
std::getline(std::cin, filename);
// open file,
// and define the openmode to output and truncate file if it exists before
std::ofstream fout(filename.c_str(), std::ios::out | std::ios::trunc);
// try to write
if (fout) fout << "Hello World!\n";
else std::cout << "failed to open file\n";
}
Some useful references:
一些有用的参考资料：
回答by Nawa
You can try this.
你可以试试这个。
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main()
{
string fileName;
cout << "Give a name to your file: ";
cin >> fileName;
fileName += ".txt"; // important to create .txt file.
ofstream createFile;
createFile.open(fileName.c_str(), ios::app);
createFile << "This will give you a new file with a name that user input." << endl;
return 0;
}
