string Lua 字符串替换

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时间:2020-09-09 00:53:44  来源:igfitidea点击:

Lua String replace

stringreplaceluagsublua-patterns

提问by Frank

How would i do this?

我该怎么做?

I got this:

我懂了:

name = "^aH^ai"
string.gsub(name, "^a", "")

which should return "Hi", but it grabs the caret character as a pattern character

应该返回“Hi”,但它将插入字符作为模式字符抓取

What would be a work around for this? (must be done in gsub)

有什么办法可以解决这个问题?(必须在 gsub 中完成)

回答by Kknd

Try:

尝试:

name = "^aH^ai"
name = name:gsub("%^a", "")

See also: http://lua-users.org/wiki/StringLibraryTutorial

另见:http: //lua-users.org/wiki/StringLibraryTutorial