php 从 SimpleXMLElement 对象获取值
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Get value from SimpleXMLElement Object
提问by kubas
I have something like this:
我有这样的事情：
$url = "http://ws.geonames.org/findNearbyPostalCodes?country=pl&placename=";
$url .= rawurlencode($city[$i]);
$xml = simplexml_load_file($url);
echo $url."\n";
$cityCode[] = array(
'city' => $city[$i],
'lat' => $xml->code[0]->lat,
'lng' => $xml->code[0]->lng
);
It's supposed to download XML from geonames. If I do print_r($xml)I get :
它应该从 geonames 下载 XML。如果我这样做，print_r($xml)我会得到：
SimpleXMLElement Object
(
[code] => Array
(
[0] => SimpleXMLElement Object
(
[postalcode] => 01-935
[name] => Warszawa
[countryCode] => PL
[lat] => 52.25
[lng] => 21.0
[adminCode1] => SimpleXMLElement Object
(
)
[adminName1] => Mazowieckie
[adminCode2] => SimpleXMLElement Object
(
)
[adminName2] => Warszawa
[adminCode3] => SimpleXMLElement Object
(
)
[adminName3] => SimpleXMLElement Object
(
)
[distance] => 0.0
)
I do as you can see $xml->code[0]->latand it returns an object. How can i get the value?
我如你所见$xml->code[0]->lat，它返回一个对象。我怎样才能获得价值？
回答by Luis Melgratti
You have to cast simpleXML Object to a string.
您必须将 simpleXML Object 转换为字符串。
$value = (string) $xml->code[0]->lat;
回答by sglessard
You can also use the magic method __toString()
您还可以使用魔术方法 __toString()
$xml->code[0]->lat->__toString()
回答by CoursesWeb
If you know that the value of the XML element is a float number (latitude, longitude, distance), you can use (float)
如果您知道 XML 元素的值是一个浮点数（纬度、经度、距离），则可以使用 (float)
$value = (float) $xml->code[0]->lat;
Also, (int)for integer number:
另外，(int)对于整数：
$value = (int) $xml->code[0]->distance;
回答by vladkras
if you don'tknow the value of XML Element, you can use
如果你不知道 XML Element 的值，你可以使用
$value = (string) $xml->code[0]->lat;
if (ctype_digit($value)) {
// the value is probably an integer because consists only of digits
}
It works when you need to determine if value is a number, because (string)will always return string and is_int($value)returns false
当您需要确定 value 是否为数字时，它会起作用，因为(string)将始终返回字符串并is_int($value)返回false
回答by dazzafact
For me its easier to use arrays than objects,
对我来说，数组比对象更容易使用，
So, I convert an Xml-Object,
所以，我转换了一个 Xml 对象，
$xml = simplexml_load_file('xml_file.xml');
$json_string = json_encode($xml);
$result_array = json_decode($json_string, TRUE);
回答by pal4life
This is the function that has always helped me convert the xml related values to array
这是一直帮助我将 xml 相关值转换为数组的函数
function _xml2array ( $xmlObject, $out = array () ){
foreach ( (array) $xmlObject as $index => $node )
$out[$index] = ( is_object ( $node ) ) ? _xml2array ( $node ) : $node;
return $out;
}
回答by Bendeberia
try current($xml->code[0]->lat)
尝试 current($xml->code[0]->lat)
it returns element under current pointer of array, which is 0, so you will get value
它返回数组当前指针下的元素，即0，因此您将获得值
回答by Zakaria Charik
you can use the '{}' to access you property, and then you can do as you wish. Save it or display the content.
您可以使用“{}”访问您的属性，然后您可以随心所欲。保存或显示内容。
$varName = $xml->{'key'};
From your example her's the code
从你的例子中，她是代码
$filePath = __DIR__ . 'Your path ';
$fileName = 'YourFilename.xml';
if (file_exists($filePath . $fileName)) {
$xml = simplexml_load_file($filePath . $fileName);
$mainNode = $xml->{'code'};
$cityArray = array();
foreach ($mainNode as $key => $data) {
$cityArray[..] = $mainNode[$key]['cityCode'];
....
}
}
回答by craned
$codeZero = null;
foreach ($xml->code->children() as $child) {
$codeZero = $child;
}
$lat = null;
foreach ($codeZero->children() as $child) {
if (isset($child->lat)) {
$lat = $child->lat;
}
}
回答by nixis
you can convert array with this function
你可以用这个函数转换数组
function xml2array($xml){
$arr = array();
foreach ($xml->children() as $r)
{
$t = array();
if(count($r->children()) == 0)
{
$arr[$r->getName()] = strval($r);
}
else
{
$arr[$r->getName()][] = xml2array($r);
}
}
return $arr;
}
