Python：使用参数（变量）执行shell脚本，但shell脚本中未读取参数
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Python: executing shell script with arguments(variable), but argument is not read in shell script
提问by creativeDrive
I am trying to execute a shell script(not command) from python:
我正在尝试从 python 执行一个 shell 脚本（不是命令）：
main.py
-------
from subprocess import Popen
Process=Popen(['./childdir/execute.sh',str(var1),str(var2)],shell=True)
execute.sh
----------
echo //does not print anything
echo //does not print anything
var1 and var2 are some string that I am using as an input to shell script. Am I missing something or is there another way to do it?
var1 和 var2 是我用作 shell 脚本输入的一些字符串。我错过了什么还是有其他方法可以做到？
Referred: How to use subprocess popen Python
采纳答案by micromoses
The problem is with shell=True. Either remove that argument, or pass all arguments as a string, as follows:
问题在于shell=True. 删除该参数，或将所有参数作为字符串传递，如下所示：
Process=Popen('./childdir/execute.sh %s %s' % (str(var1),str(var2),), shell=True)
The shell will only pass the arguments you provide in the 1st argument of Popento the process, as it does the interpretation of arguments itself.
See a similar question answered here.What actually happens is your shell script gets no arguments, so $1 and $2 are empty.
shell 只会将您在第一个参数中提供的参数Popen传递给进程，因为它本身会解释参数。请参阅此处回答的类似问题。实际发生的是你的 shell 脚本没有参数，所以 $1 和 $2 是空的。
Popen will inherit stdout and stderr from the python script, so usually there's no need to provide the stdin=and stderr=arguments to Popen (unless you run the script with output redirection, such as >). You should do this only if you need to read the output inside the python script, and manipulate it somehow.
Popen 将从 python 脚本继承 stdout 和 stderr，因此通常不需要向 Popen提供stdin=和stderr=参数（除非您运行带有输出重定向的脚本，例如>）。只有当您需要读取 python 脚本中的输出并以某种方式对其进行操作时，才应该这样做。
If all you need is to get the output (and don't mind running synchronously), I'd recommend trying check_output, as it is easier to get output than Popen:
如果您只需要获取输出（并且不介意同步运行），我建议您尝试check_output，因为获取输出比获取输出更容易Popen：
output = subprocess.check_output(['./childdir/execute.sh',str(var1),str(var2)])
print(output)
Notice that check_outputand check_callhave the same rules for the shell=argument as Popen.
请注意，check_output和check_call具有与 相同的shell=参数规则Popen。
回答by Joran Beasley
you actually are sending the arguments ... if your shell script wrote a file instead of printing you would see it. you need to communicate to see your printed output from the script ...
你实际上是在发送参数......如果你的shell脚本写了一个文件而不是打印你会看到它。您需要进行通信以查看脚本的打印输出...
from subprocess import Popen,PIPE
Process=Popen(['./childdir/execute.sh',str(var1),str(var2)],shell=True,stdin=PIPE,stderr=PIPE)
print Process.communicate() #now you should see your output
