日志文件解析python
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log file parsing python
提问by Surianan
I have a log file with arbitrary number of lines. All I need is to extract is one line of data from the log file which starts with a string “Total”. I do not want any other lines from the file.
我有一个任意行数的日志文件。我所需要的只是从日志文件中提取一行以字符串“Total”开头的数据。我不想要文件中的任何其他行。
How do I write a simple python program for this?
我如何为此编写一个简单的python程序？
This is how my input file looks
这是我的输入文件的样子
TestName id eno TPS GRE FNP
Test 1205 1 0 78.00 0.00 0.02
Test 1206 1 0 45.00 0.00 0.02
Test 1207 1 0 73400 0.00 0.02
Test 1208 1 0 34.00 0.00 0.02
Totals 64 0 129.61 145.64 1.12
I am trying to get an output file which looks like
我正在尝试获取一个看起来像的输出文件
TestName id TPS GRE
Totals 64 129.61 145.64
Ok.. So I wanted only the 1st, 2nd, 4th and 5th column from the input file but not others. I am trying the list[index] to achieve this but getting a IndexError: (list index out of range ). Also the space between 2 columns are not the same so i am not sure how to split the columns and select the ones that i want. Can somebody please help me with this. below is the program I used
好的.. 所以我只想要输入文件中的第 1、2、4 和 5 列，而不是其他列。我正在尝试使用 list[index] 来实现这一点，但得到一个 IndexError: (list index out of range )。此外，两列之间的空间也不相同，所以我不确定如何拆分列并选择我想要的列。有人可以帮我解决这个问题吗？下面是我使用的程序
newFile = open('sana.log','r')
for line in newFile.readlines():
if ('TestName' in line) or ('Totals' in line):
data = line.split('\t')
print data[0]+data[1]
采纳答案by TehTris
theFile = open('thefile.txt','r')
FILE = theFile.readlines()
theFile.close()
printList = []
for line in FILE:
if ('TestName' in line) or ('Totals' in line):
# here you may want to do some splitting/concatenation/formatting to your string
printList.append(line)
for item in printList:
print item # or write it to another file... or whatever
回答by cmd
for line in open('filename.txt', 'r'):
if line.startswith('TestName') or line.startswith('Totals'):
fields = line.rsplit(None, 5)
print '\t'.join(fields[:2] + fields[3:4])
