Scala：将元组列表扩展为元组的可变长度参数列表
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Scala: Expand List of Tuples into variable-length argument list of Tuples
提问by forker
I'm puzzled on how to expand List/Seq/Array into variable-length argument list.
我对如何将 List/Seq/Array 扩展为可变长度参数列表感到困惑。
Given that I have test_func function accepting tuples:
鉴于我有接受元组的 test_func 函数：
scala> def test_func(t:Tuple2[String,String]*) = println("works!")
test_func: (t: (String, String)*)Unit
Which works when I pass tuples:
当我传递元组时哪个有效：
scala> test_func(("1","2"),("3","4"))
works!
From reading the Scala reference I've got strong impression that the following whould work as well:
通过阅读 Scala 参考，我对以下内容也有强烈的印象：
scala> test_func(List(("1","2"),("3","4")))
<console>:9: error: type mismatch;
found : List[(java.lang.String, java.lang.String)]
required: (String, String)
test_func(List(("1","2"),("3","4")))
^
And one more desperate attempt:
还有一个绝望的尝试：
scala> test_func(List(("1","2"),("3","4")).toSeq)
<console>:9: error: type mismatch;
found : scala.collection.immutable.Seq[(java.lang.String, java.lang.String)]
required: (String, String)
test_func(List(("1","2"),("3","4")).toSeq)
How to expand List/Seq/Array into argument list?
如何将 List/Seq/Array 扩展为参数列表？
Thank you in advance!
先感谢您！
回答by Prince John Wesley
You need to add :_*.
您需要添加:_*.
scala> test_func(List(("1","2"),("3","4")):_*)
works!
scala> test_func(Seq(("1","2"),("3","4")):_*)
works!
scala> test_func(Array(("1","2"),("3","4")):_*)
works!
