laravel Vue.js 无法解析过滤器:key
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/35835214/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-09-14 13:21:27 来源:igfitidea点击:
Vue.js Failed to resolve filter: key
提问by Mike
I am following this tutorial https://laracasts.com/series/search-as-a-service/episodes/2and got stuck on the following error
我正在关注本教程https://laracasts.com/series/search-as-a-service/episodes/2并陷入以下错误
[Vue warn]: Invalid expression. Generated function body: scope.keyup:scope.search
[Vue warn]: Failed to resolve filter: key
shown in console.
显示在控制台中。
This is the code.
这是代码。
<input type="text" v-model="query" v-on="keyup: search | key 'enter'">
<div class="results">
<article v-for="movie in movies">
<h2> @{{ movie.name }}</h2>
<h4> @{{ movie.rating }}</h4>
</article>
</div>
</div>
<script src="http://cdn.jsdelivr.net/algoliasearch/3/algoliasearch.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/1.0.17/vue.js"></script>
<script>
new Vue ({
el: 'body',
data: { query: '' , movies: [] },
ready: function (){
this.client = algoliasearch('AH9XU5726U', '58fd00912ce725b3f627cfa6cb8292ee');
this.index = this.client.initIndex('getstarted_actors');
},
methods: {
search: function () {
this.index.search(this.query, function(error, results){
this.movies = results.hits;
}.bind(this));
}
}
});
</script>
Am I missing something? or is the tutorial outdated?
我错过了什么吗?还是教程过时了?
采纳答案by Ion
v-on="keyup: search | key 'enter'"
is a old version declaration, change to this:
是旧版本的声明,改成这样:
v-on:keyup.enter="search"