Python AttributeError: 'unicode' 对象没有属性 'remove'
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AttributeError: 'unicode' object has no attribute 'remove'
提问by tog
I'm trying to turn a string into a list of separate words--nothing but letters. However, as far as I can tell, unicode is causing the problems.
我试图把一个字符串变成一个单独的单词列表——除了字母之外什么都没有。但是，据我所知，unicode 导致了问题。
essay_text = ['This,', 'this,', 'this', 'and', 'that.']
def create_keywords(self):
low_text = self.essay_text.lower()
word_list = low_text.split()
abcs = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'x', 'y', 'z']
for n in word_list:
for m in n:
for l in abcs:
if m!=l:
n.remove(m)
self.keywords.setdefault(n, 0)
self.keywords[n] = word_list.count(n)
for m in bad_words:
if n==m:
del self.keywords[n]
print self.keywords
I get this error:
我收到此错误：
AttributeError: 'unicode' object has no attribute 'remove'
How can I solve this?
我该如何解决这个问题？
Update: I don't understand why my strings are in unicode. If it is relevant, here is the class that this model lies under:
更新：我不明白为什么我的字符串是 unicode。如果相关，这里是这个模型所在的类：
class Essay(models.Model):
title = models.CharField(max_length=100)
author = models.CharField(max_length=100)
email = models.EmailField(max_length=100)
essay_text = models.TextField()
sources = models.TextField()
def __unicode__(self):
return self.title
Why are my strings in in unicode?
为什么我的字符串在 unicode 中？
采纳答案by Mark Tolonen
Do you have a from __future__ import unicode_literalsin your code? That would cause Python 2.X to treat 'string'as Unicode.
你有没有from __future__ import unicode_literals在你的代码？这将导致 Python 2.X 被'string'视为 Unicode。
As others have said, strings aren't mutable and do not have a removemethod.
正如其他人所说，字符串不是可变的，也没有remove方法。
There are a couple of modules that greatly simplify your goal:
有几个模块可以极大地简化您的目标：
import re
from collections import Counter
bad_words = ['and']
def create_keywords():
essay_text = 'This, this, this and that.'
# This regular expression finds consecutive strings of lowercase letters.
# Counter counts each unique string and collects them in a dictionary.
result = Counter(re.findall(r'[a-z]+',essay_text.lower()))
for w in bad_words:
result.pop(w)
return dict(result) # return a plain dict instead of a Counter object.
Output:
输出：
>>> create_keywords()
{'this': 3, 'that': 1}
回答by óscar López
The error is explicit: the nvariable, which is a string, doesn't have a removemethod - that's because strings are immutable in Python. You'll have to create a new string without the characters you want to remove.
错误是明确的：n作为字符串的变量没有remove方法 - 那是因为字符串在 Python 中是不可变的。您必须创建一个没有要删除的字符的新字符串。
回答by John Spong
Strings are immutable, meaning they cannot be changed. What you'll really need to do is create a new string in its place with just the letters:
字符串是不可变的，这意味着它们不能被改变。您真正需要做的是在其位置创建一个仅包含字母的新字符串：
def just_letters(s):
return ''.join(l for l in s if l in string.lowercase)
word_list = [just_letters(word) for word in word_list]
