php ZF2：在控制器中获取 url 参数
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ZF2: Get url parameters in controller
提问by koenHuybrechts
I have experienced Zend Framework 1 and I've build some apps with that framework.
我使用过 Zend Framework 1，并且使用该框架构建了一些应用程序。
Now, I'm experimenting Zend Framework 2, but I'm stuck on the url parameters. I've setup my routing like this:
现在，我正在试验 Zend Framework 2，但我被困在 url 参数上。我已经像这样设置了我的路由：
// Setup for router and routes
'Zend\Mvc\Router\RouteStack' => array(
'parameters' => array(
'routes' => array(
'default' => array(
'type' => 'Zend\Mvc\Router\Http\Segment',
'options' => array(
'route' => '/[:slug]',
'constraints' => array(
'slug' => '[a-zA-Z][a-zA-Z0-9_\/-]*'
),
'defaults' => array(
'controller' => 'Htmlsite\Controller\BootController',
'action' => 'index',
'slug' => 'home'
),
),
),
'home' => array(
'type' => 'Zend\Mvc\Router\Http\Literal',
'options' => array(
'route' => '/',
'defaults' => array(
'controller' => 'Htmlsite\Controller\BootController',
'action' => 'index',
),
),
),
),
),
),
As you can see, I've tried to make a variable slug. How can I access this variable?
正如你所看到的，我试图制作一个可变的slug。我怎样才能访问这个变量？
采纳答案by bububaba
回答by Al-Punk
Or simply:
或者干脆：
$slug= $this->params('slug');
回答by Tomasz Kuter
Why not this one:
为什么不是这个：
$this->params()->fromRoute('slug');
回答by Kdecom
you can simply use this as well
你也可以简单地使用它
$this->params()->fromQuery('slug',null);
$this->params()->fromPost('slug',null);
I hope it works...
我希望它有效...
