C++ 什么是非静态成员函数？
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What is a nonstatic member function?
提问by SirYakalot
I am being told that I can't use the 'this' keyword in a class function. I'm coming from c# and i'm used to this working, but the compiler tells me that it can only be used within nonstatic member functions.
有人告诉我，我不能在类函数中使用“this”关键字。我来自 c# 并且习惯了这种工作，但是编译器告诉我它只能在非静态成员函数中使用。
D3DXVECTOR3 position;
void Position(D3DXVECTOR3 position)
{
this.position = position;
}
回答by Mark B
In C++ you need to qualify your Positionfunction with the class name:
在 C++ 中，您需要Position使用类名来限定您的函数：
void YourClassNameHere::Position(D3DXVECTOR3 position)
void YourClassNameHere::Position(D3DXVECTOR3 position)
Also from @Pubby8's answer thisis a pointer, not a reference so you need to use this->positioninstead (or consider using parameter names that don't shadow class members - I like using trailing _on my class members).
同样来自@Pubby8 的答案this是一个指针，而不是一个引用，所以你需要使用它this->position（或者考虑使用不影响类成员的参数名称 - 我喜欢_在我的类成员上使用尾随）。
Also, C++ doesn't pass by reference by default so if D3DXVECTOR3is a complicated type you'll be copying a lot of data around. Consider passing it as const D3DXVECTOR3& positioninstead.
此外，C++ 默认不通过引用传递，因此如果D3DXVECTOR3是复杂类型，您将复制大量数据。考虑将其作为const D3DXVECTOR3& position替代。
回答by Pubby
this is a pointercontaining the address of the object.
这是一个包含对象地址的指针。
D3DXVECTOR3 position;
void YourClassNameHere::Position(D3DXVECTOR3 position)
{
this->position = position;
}
Should work.
应该管用。
D3DXVECTOR3 position;
void YourClassNameHere::Position(D3DXVECTOR3 position)
{
(*this).position = position;
}
Should also work.
也应该工作。
回答by Useless
Not only is Positiona free function (not associated with a class) the way you wrote it, but thisis also a pointer, not a reference.
Position自由函数（不与类相关联）不仅是您编写它的方式，而且this还是一个指针，而不是一个引用。
D3DXVECTOR3 position;
void ClassName::Position(D3DXVECTOR3 position)
{
this->position = position;
}
or, if that's supposed to be a constructor,
或者，如果这应该是一个构造函数，
ClassName::ClassName(D3DXVECTOR3 p) : position(p)
{
}
