Java 8 - For Each 和 removeIf
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Java 8 - For Each and removeIf
提问by sathyendran a
I am trying to perform the operation using the ForEachin Java 8 by combining the removeIfmethod. But I am getting the Error.
我正在尝试ForEach通过组合removeIf方法使用Java 8 中的执行操作。但我收到错误。
I am not able to combine the forEachand removeIfin the following program:
我无法在以下程序中组合forEach和removeIf：
public class ForEachIterator {
public static void main(String[] args) {
List<Integer> ints = new ArrayList<Integer>();
for (int i = 0; i < 10; i++) {
ints.add(i);
}
System.out.println(ints);
// Getting the Error in next line
ints.forEach(ints.removeIf(i -> i%2 ==0));
System.out.println(ints);
}
}
回答by Ross Drew
There's no need for the forEach, the Lambda expression will work on all elements of the set
不需要forEach，Lambda 表达式将适用于集合的所有元素
ints.removeIf(i -> i%2==0)
removeIf: "Removes all of the elements of this collection that satisfy the given predicate"
removeIf: "移除这个集合中满足给定谓词的所有元素"
Simply...
简单地...
For each element (i) in the set (ints), remove it if (removeIf) the predicate (i%2==0) is true. This will act on the original set and return true if any elements where removed.
对于集合 ( i) 中的每个元素 ( )，ints如果 ( removeIf) 谓词 ( i%2==0) 为真，则将其删除。这将作用于原始集合并在删除任何元素时返回 true。
