在 cv2 python 中克隆图像
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Clone an image in cv2 python
提问by tintin
I'm new to opencv, here is a question, what is the python function which act the same as cv::clone() in cpp? I just try to get a rect by
我是 opencv 的新手，这里有一个问题，与 cpp 中的 cv::clone() 作用相同的 python 函数是什么？我只是想得到一个 rect
rectImg = img[10:20, 10:20]
but when I draw a line on it ,I find the line appear both on img and the rectImage,so , how can I get this done?
但是当我在上面画一条线时，我发现这条线同时出现在 img 和 rectImage 上，那么，我该如何完成呢？
采纳答案by Abid Rahman K
If you use cv2, correct method is to use .copy()method in Numpy. It will create a copy of the array you need. Otherwise it will produce only a view of that object.
如果使用cv2，正确的方法是使用.copy()Numpy 中的方法。它将创建您需要的数组的副本。否则，它只会生成该对象的视图。
eg:
例如：
In [1]: import numpy as np
In [2]: x = np.arange(10*10).reshape((10,10))
In [4]: y = x[3:7,3:7].copy()
In [6]: y[2,2] = 1000
In [8]: 1000 in x
Out[8]: False # see, 1000 in y doesn't change values in x, parent array.
回答by yildirim
You can simply use Python standard library. Make a shallow copy of the original image as follows:
您可以简单地使用 Python 标准库。制作原始图像的浅拷贝，如下所示：
import copy
original_img = cv2.imread("foo.jpg")
clone_img = copy.copy(original_img)
回答by Hyman Guy
My favorite method uses cv2.copyMakeBorder with no border, like so.
我最喜欢的方法使用没有边框的 cv2.copyMakeBorder，就像这样。
copy = cv2.copyMakeBorder(original,0,0,0,0,cv2.BORDER_REPLICATE)
回答by Ash Ketchum
The first answer is correct but you say that you are using cv2 which inherently uses numpy arrays. So, to make a complete different copy of say "myImage":
第一个答案是正确的，但您说您使用的是 cv2，它本质上使用 numpy 数组。因此，要制作一个完全不同的“myImage”副本：
newImage = myImage.copy()
The above is enough. No need to import numpy.
以上就够了。无需导入 numpy。
