java 如何在 Hibernate 应用程序中处理数据库空值？
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How to handle database null values in Hibernate Application?
提问by Raj
I am getting " org.hibernate.PropertyAccessException" due to null values in my database table. How to handle the exception?
由于我的数据库表中的空值，我收到“org.hibernate.PropertyAccessException”。如何处理异常？
My files are
我的文件是
FetchTest.java
获取测试文件
package com.raj.java.hiberanteDemos;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;
public class FetchTest {
public static void main(String[] args) {
Configuration cfg=new Configuration().configure("hibernate.cfg.xml");
SessionFactory factory=cfg.buildSessionFactory();
Session session1=factory.openSession();
Employee emp1=(Employee)session1.get(Employee.class,7839);
System.out.println(emp1.getEmpno()+" "+emp1.getEname()+" "+emp1.getSal());
session1.close();
Session session2=factory.openSession();
Employee emp2=(Employee)session2.load(Employee.class,7839);
System.out.println(emp2.getEmpno()+" "+emp2.getEname()+" "+emp2.getSal());
session2.close();
}
}Employee.java
雇员.java
package com.raj.java.hiberanteDemos;
import java.sql.Date;
class Employee {
private int empno, mgr, deptnumber;
private String ename, job;
private double sal, comm;
private Date hiredate;
public int getEmpno() {
return empno;
}
public void setEmpno(int empno) {
this.empno = empno;
}
public int getMgr() {
return mgr;
}
public void setMgr(int mgr) {
this.mgr = mgr;
}
public int getDeptnumber() {
return deptnumber;
}
public void setDeptnumber(int deptnumber) {
this.deptnumber = deptnumber;
}
public String getJob() {
return job;
}
public void setJob(String job) {
this.job = job;
}
public double getComm() {
return comm;
}
public void setComm(double comm) {
this.comm = comm;
}
public Date getHiredate() {
return hiredate;
}
public void setHiredate(Date hiredate) {
this.hiredate = hiredate;
}
public String getEname() {
return ename;
}
public void setEname(String ename) {
this.ename = ename;
}
public double getSal() {
return sal;
}
public void setSal(double sal) {
this.sal = sal;
}
}hibernate.cfg.xml
休眠文件.cfg.xml
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hbm2ddl.auto">update</property>
<property name="dialect">org.hibernate.dialect.Oracle9Dialect
</property>
<property name="connection.url">someValidurl</property>
<property name="connection.username">username</property>
<property name="connection.password">password</property>
<property name="connection.driver_class">oracle.jdbc.driver.OracleDriver</property>
<property name="hibernate.show_sql">true</property>
<property name="cache.provider_class">org.hibernate.cache.EhCacheProvider</property>
<property name="hibernate.cache.use_second_level_cache">true</property>
<mapping resource="employee.hbm.xml"></mapping>
</session-factory>
</hibernate-configuration>employee.hbm.xml
员工档案.xml
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<!-- <class name="com.javatpoint.mypackage.Employee" table="employee"> <id
name="empid"> <generator class="assigned"></generator> </id> <property name="firstName"></property>
<property name="lastName"></property> </class> -->
<class name="com.raj.java.hiberanteDemos.Employee" table="emp">
<id name="empno" type="int" column="EMPNO">
<generator class="increment" />
</id>
<property name="ename" type="java.lang.String" />
<property name="mgr" type="int" />
<property name="deptnumber" type="int" column="deptno" />
<property name="job" type="java.lang.String" />
<property name="sal" type="double" />
<property name="comm" type="double" />
<property name="hiredate" type="java.sql.Date" />
</class>
</hibernate-mapping>When I ran this application I am getting below error message.
当我运行这个应用程序时，我收到以下错误消息。
log4j:WARN No appenders could be found for logger (org.hibernate.cfg.Environment).
log4j:WARN Please initialize the log4j system properly.
Hibernate: select employee0_.EMPNO as EMPNO0_0_, employee0_.ename as ename0_0_, employee0_.mgr as mgr0_0_, employee0_.deptno as deptno0_0_, employee0_.job as job0_0_, employee0_.sal as sal0_0_, employee0_.comm as comm0_0_, employee0_.hiredate as hiredate0_0_ from emp employee0_ where employee0_.EMPNO=?
Exception in thread "main" org.hibernate.PropertyAccessException: exception setting property value with CGLIB (set hibernate.cglib.use_reflection_optimizer=false for more info) setter of com.raj.java.hiberanteDemos.Employee.setMgr
at org.hibernate.tuple.PojoEntityTuplizer.setPropertyValuesWithOptimizer(PojoEntityTuplizer.java:215)
at org.hibernate.tuple.PojoEntityTuplizer.setPropertyValues(PojoEntityTuplizer.java:185)
at org.hibernate.persister.entity.AbstractEntityPersister.setPropertyValues(AbstractEntityPersister.java:3232)
at org.hibernate.engine.TwoPhaseLoad.initializeEntity(TwoPhaseLoad.java:129)
at org.hibernate.loader.Loader.initializeEntitiesAndCollections(Loader.java:842)
at org.hibernate.loader.Loader.doQuery(Loader.java:717)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:224)
at org.hibernate.loader.Loader.loadEntity(Loader.java:1785)
at org.hibernate.loader.entity.AbstractEntityLoader.load(AbstractEntityLoader.java:47)
at org.hibernate.loader.entity.AbstractEntityLoader.load(AbstractEntityLoader.java:41)
at org.hibernate.persister.entity.AbstractEntityPersister.load(AbstractEntityPersister.java:2730)
at org.hibernate.event.def.DefaultLoadEventListener.loadFromDatasource(DefaultLoadEventListener.java:365)
at org.hibernate.event.def.DefaultLoadEventListener.doLoad(DefaultLoadEventListener.java:346)
at org.hibernate.event.def.DefaultLoadEventListener.load(DefaultLoadEventListener.java:123)
at org.hibernate.event.def.DefaultLoadEventListener.proxyOrLoad(DefaultLoadEventListener.java:177)
at org.hibernate.event.def.DefaultLoadEventListener.onLoad(DefaultLoadEventListener.java:87)
at org.hibernate.impl.SessionImpl.fireLoad(SessionImpl.java:862)
at org.hibernate.impl.SessionImpl.get(SessionImpl.java:799)
at org.hibernate.impl.SessionImpl.get(SessionImpl.java:792)
at com.raj.java.hiberanteDemos.FetchTest.main(FetchTest.java:13)
Caused by: net.sf.cglib.beans.BulkBeanException
at com.raj.java.hiberanteDemos.Employee$$BulkBeanByCGLIB$2cfd75.setPropertyValues(<generated>)
at org.hibernate.tuple.PojoEntityTuplizer.setPropertyValuesWithOptimizer(PojoEntityTuplizer.java:212)
... 19 more
Caused by: java.lang.NullPointerException
... 21 moremy emp table data
我的 emp 表数据
when I update all the null values with 0 or some other values its working fine.
当我用 0 或其他一些值更新所有空值时，它工作正常。
Please help me in solving the error without updating null values in database table.
请帮助我解决错误而不更新数据库表中的空值。
Thanks in Advance, Raj
提前致谢，拉吉
采纳答案by jmcg
I would personally recommend to actually "clean" the database values, maybe setting the column not nullable.
我个人建议实际“清理”数据库值，也许将列设置为不可为空。
But if this can't be done, what you can do is modify your setters, so that it checks for null:
但是，如果这无法完成，您可以做的是修改您的设置器，以便它检查null：
public void setComm(Double comm) {
if(null != comm){
this.comm = comm;
}else{
this.comm = 0;
}
}
hope this helps
希望这可以帮助
回答by SCI
Your mgr-Property is int, which does not allow null. Change it to Integer, which allows null. Or make a default value for your mgr column.
您的 mgr-Property 是int，它不允许null。将其更改为Integer，这允许null。或者为您的 mgr 列设置默认值。
回答by Isaac Riley
The best way to avoid Hibernate's attempts at setting null values to primitives is to use Wrapper classes (Integer, Long, Double...); and especially, if you need to tack on a column or 2 to an existing table. Auto-boxing is your friend.
避免 Hibernate 尝试为原语设置空值的最佳方法是使用 Wrapper 类（Integer、Long、Double...）；尤其是，如果您需要将一列或 2 列添加到现有表中。自动拳击是你的朋友。
