java 正则表达式在第 n 次出现管道字符后匹配子字符串
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regex to match substring after nth occurence of pipe character
提问by Ramesh
i am trying to build one regex expression for the below sample text in which i need to replace the boldtext. So far i could achieve this much
((\|)).*(\|)which is selecting the whole string between the first and last pip char. i am bound to use apache or java regex.
我正在尝试为下面的示例文本构建一个正则表达式，我需要在其中替换粗体文本。到目前为止，我可以做到这一点
((\|)).*(\|)，即选择第一个和最后一个 pip 字符之间的整个字符串。我一定会使用 apache 或 java regex。
Sample String: where text length between pipes may vary
示例字符串：管道之间的文本长度可能会有所不同
1.1|ProvCM|111111111111|**10.15.194.25**|10.100.10.3|10.100.10.1|docsis3.0
回答by anubhava
To match part after nthoccurrence of pipe you can use this regex:
要在nth管道出现后匹配部分，您可以使用此正则表达式：
/^(?:[^|]*\|){3}([^|]*)/
Here n=3
这里 n=3
It will match 10.15.194.25in matched group #1
它将10.15.194.25在匹配组 #1 中匹配
回答by vks
^((?:[^|]*\|){3})[^|]+
You can use this.Replace by $1<anything>.See demo.
您可以使用 this.Replace by $1<anything>.See 演示。
https://regex101.com/r/tP7qE7/4
https://regex101.com/r/tP7qE7/4
This here captures from startof string to |and then captures 3 such groups and stores it in $1.The next part of string till |is what you want.Now you can replace it with anything by $1<textyouwant>.
这在这里捕获 from startof string to|然后捕获 3 个这样的组并将其存储在.The $1next part of string until|是你想要的。现在你可以用任何东西替换它$1<textyouwant>。
回答by Denys Séguret
Here's how you can do the replacement:
更换方法如下：
String input = "1.1|ProvCM|111111111111|10.15.194.25|10.100.10.3|10.100.10.1|docsis3.0";
int n = 3;
String newValue = "new value";
String output = input.replaceFirst("^((?:[^|]+\|){"+n+"})[^|]+", ""+newValue);
This builds:
这构建：
"1.1|ProvCM|111111111111|new value|10.100.10.3|10.100.10.1|docsis3.0"
