Javascript 使用Underscorejs，如何查找一个数组是否包含另一个数组？
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With Underscorejs, how to find whether an array contains another array?
提问by epascarello
I have this
我有这个
var matches = bookmarks.filter(function(x) {
return _.contains(x.get("tags"), 'apple');
});
Which will return the bookmark objects that have the apple tags
这将返回具有苹果标签的书签对象
I want to put an array there instead to pull and all the bookmarks that have the matching values, similar to this
我想在那里放一个数组来拉取所有具有匹配值的书签，类似于这个
var matches = bookmarks.filter(function(x) {
return _.contains(x.get("tags"), ['apple','orange']);
});
This doesn't work, any way to get it to work?
这不起作用，有什么办法让它起作用吗？
EDIT: Im sorry, bookmarks is a collection and im trying to return the models that have the apple and orange tags
编辑：对不起，书签是一个集合，我试图返回带有苹果和橙色标签的模型
回答by epascarello
If tags is a string, your code it would be
如果标签是一个字符串，你的代码就是
return _.indexOf(x.get("tags"), ['apple','orange']) > -1;
Example with indexOf : jsFiddle
indexOf 示例：jsFiddle
If tags is an array, you can use intersection
如果标签是一个数组，你可以使用交集
return _.intersection(['apple','orange'], x.get("tags")).length > 0;
Example with intersection: jsFiddle
带交点的示例：jsFiddle
回答by pimvdb
There doesn't seem to be a function for that in underscore. However, you can easily combine other functions to accomplish this:
下划线中似乎没有该功能。但是，您可以轻松地结合其他功能来完成此操作：
_.mixin({
containsAny: function(arr, values) {
// at least one (.some) of the values should be in the array (.contains)
return _.some(values, function(value) {
return _.contains(arr, value);
});
}
});
