如何通过命令行将数组传递给python
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How to pass an array to python through command line
提问by Luyao Wang
I am trying to pass an array to the python
我正在尝试将数组传递给 python
import sys
arr = sys.argv[1]
print(arr[2])
My command is
我的命令是
python3 test.py [1,2,3,4,5] 0
I hope the result it
希望结果吧
2
However, it is
然而，它是
,
回答by Barmar
The elements of argvare strings, they're not parsed like literals in the program.
的元素argv是字符串，它们不像程序中的文字那样被解析。
You should just pass a comma-separated string (without the brackets):
您应该只传递一个逗号分隔的字符串（不带括号）：
python3 test.py 1,2,3,4,5 0
and then use split()to convert it to an array.
然后使用split()将其转换为数组。
import sys
arr = sys.argv[1].split(',')
print(arr[2])
回答by alexis
Commandline arguments are strings. Even integers have to be converted from string to int. If you use the list syntax you show in your example, you'll need to run the argument through some sort of parser (your own parser, something from ast, or eval-- but don't use eval). But there's a simpler way: Just write the arguments separately, and use a slice of sys.argvas your list. Space-separated arguments is the standard way to pass multiple arguments to a commandline program (e.g., multiple filenames to less, rm, etc.).
命令行参数是字符串。甚至整数也必须从字符串转换为int. 如果您使用示例中显示的列表语法，则需要通过某种解析器（您自己的解析器、来自ast或eval-- 但不要使用eval）来运行参数。但是有一种更简单的方法：只需单独编写参数，并使用一个切片sys.argv作为您的列表。空间分隔参数是将多个参数传递给一个命令行程序（例如，多个文件名到标准方式less，rm等）。
python3 test.py -n a b c 1 2 3
First you'd identify and skip arguments that have a different purpose (-nin the above example), then simply keep the rest:
首先，您将识别并跳过具有不同目的的参数（-n在上面的示例中），然后只需保留其余部分：
arr = sys.argv[2:]
print(arr[3]) # Prints "1"
PS. You also need to protect any argument from the shell, by quoting any characters with special meaning(*, ;, spaces that are part of an argument, etc.). But that's a separate issue.
附注。您还需要通过引用具有特殊含义的任何字符（*、;、作为参数一部分的空格等）来保护 shell 中的任何参数。但这是一个单独的问题。
