Linux Makefile 错误：未找到命令 - 创建共享库时
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Makefile Error : Command Not Found- while creating a shared library
提问by Eternal Learner
I have 4 .c files hello.c,here.c,bye.cand main.c.
One header file mylib.h
我有4个.c文件hello.c，here.c，bye.c和main.c。一个头文件mylib.h
The contents are as follows
内容如下
hello.c
你好ç
#include<stdio.h>
void hello()
{
printf("Hello!\n");
}
here.c
这里.c
#include<stdio.h>
void here()
{
printf("I am here \n");
}
bye.c
再见
#include<stdio.h>
void bye()
{
printf("Bye,Bye");
}
main.c
主文件
#include<stdio.h>
#include "mylib.h"
int main()
{
hello();
here();
bye();
return 1;
}
mylib.h
mylib.h
#ifndef _mylib_
#define _mylib_
void hello();
void here();
void bye();
#endif
The makefile for creating a static lib is : Makefile
创建静态库的makefile是：Makefile
#Which Compiler
CC = gcc
#Compiler Flags
CFLAGS = - Wall -c -fPIC
DYNLINKFLAGS = -shared -W1,-soname,[email protected]
PROG = main
PROG_OBJS = main.c
LIB = mylib
LIB_FILES = libmylib.so
LIB_MINOR = $(LIB_FILES).0.1
LIB_RELEASE = $(LIB_MINOR).0
LIB_OBJS = hello.o here.o bye.o
PATH = /home/srinivasa/cspp51081/labs/srinivasa.lab2.1
all: $(LIB_FILES) $(PROG)
#Create Lib with this file
$(LIB_FILES): $(LIB_OBJS)
$(CC) $(DYNLINKFLAGS) $^
ln -sf $(LIB_RELEASE) $(LIB_MINOR)
ln -sf $(LIB_MINOR) $@
ln -sf $@ [email protected]
#Compiling main program and link with shared library
$(PROG): $(PROG_OBJS)
$(CC) -o $(PROG) $(PORG_OBJS) -l$(LIB) -L$(PATH)
main.o: main.c
hello.o: hello.c
here.o: here.c
bye.o: bye.c
#clean files
clean:
rm -rf $(LIB_OBJS) $(LIB_FILES) $(LIB_RELEASE) $(LIB_MINOR) libmylib.so.0
Problem: When I execute the command
问题：当我执行命令时
make -f Makefile all
I get the error:
我收到错误：
gcc -Wall -fPIC -c -o hello.o hello.c make: gcc: Command not found make: *[hello.o] Error 127
gcc -Wall -fPIC -c -o hello.o hello.c make: gcc: Command not found make: *[hello.o] Error 127
Questions : How do I resolve this?
问题 ： How do I resolve this?
采纳答案by Ziffusion
+++++
+++++
OK. Lets revert to your original code, but with a small difference.
好的。让我们恢复到您的原始代码，但有一点不同。
Change DYNLINKFLAGS back to:
将 DYNLINKFLAGS 改回：
DYNLINKFLAGS = -shared -Wl,-soname,[email protected]
Then change the library link to:
然后将库链接更改为：
$(CC) $(DYNLINKFLAGS) -o $(LIB_RELEASE) $^
ln -sf $(LIB_RELEASE) $(LIB_MINOR)
ln -sf $(LIB_MINOR) $@
ln -sf $@ [email protected]
Do "rm -f lib*", build and then post make output.
执行“rm -f lib*”，构建然后发布 make 输出。
回答by codaddict
There are a few bugs (just typos) I can see is:
我可以看到的一些错误（只是错别字）是：
space between
-andWall:CFLAGS = - Wall -c -fPIC ^PORG_OBJSshould bePROG_OBJS$(CC) -o $(PROG) $(PORG_OBJS) -L$(PATH) ^^^^You are doing an absolute assignment to
PATH. Now every executable called in makefile will be search in that directory. Sincegccis not found in that directory you get this error. To fix this you can either use a differentvariable name or add your directory to current path as:PATH := $(PATH):/home/srinivasa/cspp51081/labs/srinivasa.lab2.1 ^ ^^^^^^^^
-和之间的空间Wall：CFLAGS = - Wall -c -fPIC ^PORG_OBJS应该PROG_OBJS$(CC) -o $(PROG) $(PORG_OBJS) -L$(PATH) ^^^^您正在对
PATH. 现在 makefile 中调用的每个可执行文件都将在该目录中搜索。由于gcc未在该目录中找到，您会收到此错误。要解决此问题，您可以使用不同的变量名称或将您的目录添加到当前路径：PATH := $(PATH):/home/srinivasa/cspp51081/labs/srinivasa.lab2.1 ^ ^^^^^^^^
回答by Ziffusion
Try changing this line from:
尝试从以下位置更改此行：
$(CC) -o $(PROG) $(PORG_OBJS) -l$(LIB) -L$(LIBPATH)
to:
到：
$(CC) -o $(PROG) $(PORG_OBJS) -L$(LIBPATH) -l$(LIB)
The -L flag needs to precede the -l flags.
-L 标志需要在 -l 标志之前。
回答by Ziffusion
OK. First change:
好的。第一个变化：
DYNLINKFLAGS = -shared -W1,-soname,[email protected]
to
到
DYNLINKFLAGS = -shared -W1,-soname,$@
Then change:
然后改变：
ln -sf $(LIB_RELEASE) $(LIB_MINOR)
ln -sf $(LIB_MINOR) $@
ln -sf $@ [email protected]
To:
到：
ln -sf $@ $(LIB_RELEASE)
ln -sf $@ $(LIB_MINOR)
ln -sf $@ [email protected]
Then post the library links and the final executable link.
然后发布库链接和最终的可执行链接。
